Question

A bag contains 4 yellow marbles and 6 green marbles. Two marbles are drawn at random. One marble is drawn and not replaced. Then a second marble is drawn. What is the probability that the first marble is green and the second one is yellow?
1/15

4/15

1/6

3/2

Answer 1

$\frac{6}{10} \times \frac{4}{9} \\ = \frac{24}{90} \\ = \frac{4}{15}$

Answer is 2nd option, 4/15

Hope this helps. - M