Answer: English?>
Step-by-step explanation:
Initial velocity = 0 m/s
Acceleration = 9.8 m/s²
Time = 3.1 s
s = ut + 1/2 at²
s = 1/2 x 9.8 x 3.1²
s = 47.1 m
The building is 47.1 meters tall
Answer:
O=30° or O=29°
Step By Step Explanation:
∠α =arcsin( a/c )
= arcsin(4/8)
= arcsin(0.5)
= 0.5 rad = 30° = 29°
I Hope This Helps. I Gave you 2 answers just in case 1 is Wrong. And I Hope you Understand This Calculation, I Used Different Variables and the arcsin thing is something my teacher told my class to use, and I Have no Idea what it means because my teacher never explained what it meant, Sadly.
The question here is how long does it take for a falling
person to reach the 90% of this terminal velocity. The computation is:
The terminal velocity vt fulfills v'=0. Therefore vt=g/c,
and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the
differential equation shows that the time needed to reach velocity v is
t= ln [g / (g-c*v)] / c.
With v=.9 vt =.9 g/c,
t = ln [10] /c = 6.4 sec.
So one trip = 4 km
two trips = 8
8 + 4 = 12
i believe your answer is 12
Thanks!
