We have that
<span>y=2x+4--------> equation 1
3x−6y=3-------> equation 2
step 1
</span>I substitute the value of y in equation 1 for the value of y in equation 2<span>
so
</span>3x−6*[2x+4]=3-------> 3x-12x-24=3
-9x=3+24
-9x=27------> 9x=-27
x=-27/9
x=-3
step 2
<span>I substitute the value of x in equation 1 to get the value of y</span>
y=2x+4--------> y=2*(-3)+4--------> y=-6+4
y=-2
the answer is
the solution is the point (-3,-2)
x=-3
y=-2
I hope this helps you
a=4
b=9
c= -1
disctirminant =b^2-4ac
disctirminant =9^2-4.4. (-1)
disctirminant =97
x1=-9+square root of 97/2.4= -9+square root of 97/8
x2= -9-square root of 97/2.4= -9-square root of 97/8
Part A:
The probability that a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

Given that the average precipitation in
Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>a randomly selected year will have precipitation greater than 18 inches for the first 7 months is given by:

Part B:
</span>The probability that an n randomly selected samples of a normally distributed data with a mean, μ and
standard deviation, σ is greater than a given value, a is given by:

Given that the average precipitation in
Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>5 randomly selected years will have precipitation greater than 18 inches for the first 7 months is given by:
</span>
Answer:
b. area = 18 square units
Step-by-step explanation:
area of a triangle = 1/2 * base * height
area = 1/2 (6+3) + (6-2)
area = 1/2 * 9 * 4
area = 18 square units
therefore the answer is b.