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lianna [129]
3 years ago
5

In a bag, there are 5 cards numbered 1 to 5. Each time a card is randomly selected, it I'd replaced in the bag. What is the prob

ability Marsha will select an even-numbered card first and then an odd-numbered card?
Mathematics
2 answers:
pav-90 [236]3 years ago
6 0
There is a 2 out of 5 chance of pulling an even\frac{2}{5}
there is a 3 out of 5 chance of pulling an odd the second time\frac{3}{5}

\frac{2}{5}*\frac{3}{5}=\frac{6}{25}

there is a 6 out of 25 chance of it happening in that order
sweet [91]3 years ago
3 0

Out of 5 cards in the bag ...

-- There are 2 even numbers . . . 2 and 4 .

-- There are 3 odd numbers . . . 1, 3, and 5 .

So EITHER time, the probability of pulling an even number is  2/5 ,
and the probability of pulling an odd number is  3/5 .

The probability of pulling an even number the first time
AND an odd number the second time is

       (2/5) x (3/5)  =  6/25  =  <em>24%</em> .

 
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A= [2, 3; 2, 1], B=[3; 5]. Find AB &amp; BA if possible
oksano4ka [1.4K]

Answer:

The value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right] and it's not possible to multiply BA.

Step-by-step explanation:

Consider the provided matrices.

A=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right], B=\left[\begin{array}{ccc}3\\5\end{array}\right]

Two matrices can be multiplied if and only if first matrix has an order m × n and second matrix has an order n × v.

Multiply AB

Matrix A has order 2 × 2  and matrix B has order 2 × 1. So according to rule we can multiply both the matrix as shown:

AB=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right] \left[\begin{array}{ccc}3\\5\end{array}\right]

AB=\left[\begin{array}{ccc}2\times 3+3\times 5\\2\times 3+1\times 5\end{array}\right]

AB=\left[\begin{array}{ccc}6+15\\6+5\end{array}\right]

AB=\left[\begin{array}{ccc}21\\11\end{array}\right]

Hence, the value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right]

Now calculate the value of BA as shown:

Multiply BA

Matrix B has order 2 × 1  and matrix A has order 2 × 2. So according to rule we cannot multiply both the matrix.

We can multiply two matrix if first matrix has an order m × n and second matrix has an order n × v.

That means number of column of first matrix should be equal to the number of rows of second matrix.

Hence, it's not possible to multiply BA.

5 0
3 years ago
25 points to whoever solves the whole page
faust18 [17]

Answer:

row 1

5

4

-9

10

23

2

-19

18

-13

row 2

7

10

25

31

42

-2

23

11

23

row 3

-3

15

-11

37

-7

3

35

3

0

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Which of these systems of equations shows the solution for the graph?
I am Lyosha [343]

Answer:

C)

Step-by-step explanation:

Note that one of the lines is simply y=-1 for any x, so we can dismiss the only answer without y=-1. That rejected answer is A)

Now let's notice, that the other line is decreasing y when increasing x. That tells us that in the equation y = ax + b, a has to be negative. This brings us to reject option D).

What is the y of that line for x = 0? Because y = ax + b, for x = 0 we will get the value of b. This is called the intercept. The line is at y=4 for x=0, so we know that the b in the equation must be positive 4. This fits answer C, but rejects answer B). And so, we have found that C) is the only possible answer.

4 0
3 years ago
What’s the answer to this math problem
nydimaria [60]

Answer:$240.00

Step-by-step explanation:

$240.00

8 0
3 years ago
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B. Were you able to find the solution(s) of each Mathematical sentence? How did
alexandr1967 [171]

Answer:

Evaluate each given numbers, expressions or equation.

Check the values or numbers.

Now in order to solve we proceed in the manner

  • Read the problem
  • Analyze the problem
  • Write the given variables
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  • Write the equation
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4 0
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