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zhannawk [14.2K]
2 years ago
12

Evaluate if a= 28 and b= -3 a/4+b

Mathematics
1 answer:
patriot [66]2 years ago
8 0

Answer:

4

Step-by-step explanation:

divide the numbers


subtract the numbers


final answer:
= 4

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THERE IS MORE THAN ONE ANSWER THEIR IS UP TO 3 ANSWERS
kvv77 [185]

Answer:

-4.01, -4, -7

Step-by-step explanation:

equation:

-x + 6 ≥ 10

substitute each number for x

- (-3.9) + 6 ≥ 10 = (negatives cancel each other out) 3.9 + 6 = 9.9 ≥ 10 (incorrect)

-4 + 6 ≥ 10 = 2 ≥ 10 (incorrect)

- (-4.01) + 6 ≥ 10 = (negatives cancel each other out) 10.01 ≥ 10 (correct)

- (-4) + 6 ≥ 10 = (negatives cancel each other out) 10 ≥ 10 (correct)

-4.01 + 6 ≥ = 1.99 ≥ 10 (incorrect)

-3.9 + 6 ≥ 10 = 2.1 ≥ 10 (incorrect)

-0 + 6 ≥ 10 = 6 ≥ 10 (incorrect)

- (-7) + 6 ≥ 10 = (negatives cancel each other out) 11 ≥ 10 (correct)

6 0
3 years ago
Given that ∠S ≅ ∠A, and AB ≅ ST , what is the third congruence needed to prove that ΔABC ≅ ΔSTU by ASA?
Olenka [21]

Answer:

angle-side-angle. that's my answer

7 0
2 years ago
Which of the following is equal to the fraction below?
Vesna [10]

In mathematics there is a rule of exponents where we can "distribute" the powers/exponents in the numerator and denominator of any expression. Therefore, given an expression as (\frac{a}{b})^n, the exponent n can be "distributed" as: (\frac{a}{b})^n= \frac{a^n}{b^n}.

In our case, the power, n=11; a=7 and b=4. Thus, the expression (\frac{7}{4})^{11}, can be written as \frac{7^{11}}{4^{11}}.

Thus, out of the given options, option A is the correct option.

6 0
3 years ago
Read 2 more answers
Apply the Distributive Property.<br> -3(4y-9)
olganol [36]
-12y + 27

So what you do is take the numbers outside the (parentheses) which in this case is -3 and then multiply it to positive 4y and -9 to get your answer!
8 0
3 years ago
Read 2 more answers
What is one of the solutions to the following system of equations?
Amanda [17]

Answer:

(8,-1)

Step-by-step explanation:

Given :   x^{2} +y^{2} =65

               x+y=7

To Find: solution of given system of equations.

Solution:

Equation a :   x^{2} +y^{2} =65

Equation b :  x+y=7

Substitute the value of y from equation b in equation a

y from equation b : y = 7-x

Now substitute value of y in equation a

Thus equation a becomes:

 x^{2} +(7-x)^{2} =65

x^{2} +49+x^{2}-14x =65

2x^{2} -14x =65-49

x^{2} -7x -8=0

x^{2} -8x+x -8=0

x(x-8)+1(x-8)=0

(x+1)(x-8)=0

⇒ x= -1 and x = 8

Now substitute values of x  in equation b to obtains values of y

⇒ x+y=7

for x = -1

⇒ -1+y=7

⇒ y=7+1

⇒ y=8

Thus (x,y)=(-1,8)

For x =8

⇒ 8+y=7

⇒ y=7-8

⇒ y=-1

Thus (x,y)=(8,-1)

Hence Option A is the correct solution .


6 0
3 years ago
Read 2 more answers
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