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Temka [501]
3 years ago
13

How do I solve x-y=11 2x+y=19

Mathematics
2 answers:
Margarita [4]3 years ago
5 0
<span>x-y=11 2x+y=19
x=11+y
2(11+y)+y=19
22+2y+y=19
3y=-3
y=-1
x=11-1=10</span>
marta [7]3 years ago
3 0

Answer: X = 10 and Y = -1

Step-by-step explanation:

X - Y = 11

X = 11 + Y (plug into the other equation)

2X + Y = 19

2 ( 11+Y ) + Y = 19

22 + 2Y + Y = 19

22 + 3Y = 19

-22 -22

————————-

3Y = -3

Y = -1 (plug into the original formula)

X - Y = 11

X - (-1) = 11

X + 1 = 11

-1 -1

—————

X = 10

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angle F=180°-(40+87)°=53°
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The answer is
x=16.3 cm
5 0
3 years ago
if the pet store had 10 more birds the number of dogs would be double the number of birds what number should be on the scale exp
murzikaleks [220]

Answer:

one that fits

Step-by-step explanation:

#Bird+10 so #dog=2(#birds+10)

5 0
3 years ago
Read 2 more answers
the table shows the number of lift tickets and ski rentals sold to two different groups. Is it possible to determine how much ea
zysi [14]
It is possible

Group 1 : 684 divided by 36 = 19$

Group 2 : 456 divided by 24 = 19$

Therefore, both groups 1 and 2 charge $19 for each ticket

7 0
3 years ago
A student committee is to consist of 2 freshmen, 5 sophomores, 4 juniors, and 3 seniors. If 6 freshmen, 13 sophomores, 8 juniors
mezya [45]
<h3>Answer:  491,891,400</h3>

Delete the commas if necessary.

============================================================

Explanation:

There are 6 freshmen total and we want to pick 2 of them, where order doesn't matter. The reason it doesn't matter is because each seat on the committee is the same. No member outranks any other. If the positions were labeled "president", "vice president", "secretary", etc, then the order would matter.

Plug n = 6 and r = 2 into the nCr combination formula below

n C r = \frac{n!}{r!(n-r)!}\\\\6 C 2 = \frac{6!}{2!*(6-2)!}\\\\6 C 2 = \frac{6!}{2!*4!}\\\\6 C 2 = \frac{6*5*4!}{2!*4!}\\\\ 6 C 2 = \frac{6*5}{2!}\\\\ 6 C 2 = \frac{6*5}{2*1}\\\\ 6 C 2 = \frac{30}{2}\\\\ 6 C 2 = 15\\\\

This tells us there are 15 ways to pick the 2 freshmen from a pool of 6 total.

Repeat those steps for the other grade levels.

n = 13 sophomores, r = 5 selections leads to nCr = 13C5 = 1287. This is the number of ways to pick the sophomores.

You would follow the same type of steps shown above to get 1287. Let me know if you need to see these steps.

Similarly, 8C4 = 70 is the number of ways to pick the juniors.

Lastly, 14C3 = 364 is the number of ways to pick the seniors.

-----------------------------

To recap, we have...

  • 15 ways to pick the freshmen
  • 1287 ways to pick the sophomores
  • 70 ways to pick the juniors
  • 364 ways to pick the seniors

Multiply out those values to get to the final answer.

15*1287*70*364 = 491,891,400

This massive number is a little under 492 million.

7 0
2 years ago
What is the answer and how do u get that answer
earnstyle [38]
Let me see a better picture
3 0
3 years ago
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