Answer:
The percentage of the students scored higher than 89% is 15.87%
Step-by-step explanation:
we are given
The average test scores for a particular test in algebra was 84
so, mean is 84
a standard deviation of 5
so,
we have
x=89
now, we can use z-score formula
now, we can plug values
now, we can use calculator
and we get
So,
The percentage of the students scored higher than 89% is 15.87%
Take the deritivive
remember
the deritivive of f(x)/g(x)=(f'(x)g(x)-g'(x)f(x))/(g(x)^2)
so
deritiveive is ln(x)/x is
remember that derivitive of lnx is 1/x
so
(1/x*x-1lnx)/(x^2)=(1-ln(x))/(x^2)
the max occurs where the value is 0
(1-ln(x))/(x^2)=0
times x^2 both sides
1-lnx=0
add lnx both sides
1=lnx
e^1=x
e=x
see if dats a max or min
at e/2, the slope is positive
at 3e/2, the slope is negative
changes from positive to negative at x=e
that means it's a max
max at x=e
I realize I didn't find the max point, so
sub back
ln(x)/x
ln(e)/e
1/e
the value of the max would be 1/e occuring where x=e
4th option is answer (1/e) because that is the value of the maximum (which happens at x=e)
Answer:B
Step-by-step explanation:
The answer should be 2.96
Answer : Image 3
Which table shows a function that is decreasing over the interval (−2, 0)?
We look at the interval -2 to 0 on x
In option 1 table , f(x) is 0 then -5 and then becomes 0
It means -2 to -1 , f(x) decreases but from -1 to 0 y values increases
In option 2 table , f(x) is increasing from -15 to -5
In option 3 table, f(x) values goes on decreasing over the interval -2 to 0
So , option 3 table shows a function that is decreasing over the interval (−2, 0)
