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3 years ago

Suppose we describe the weather as either hot (Upper H) or cloudy (Upper C). Answer parts (a) and (b) below.

Mathematics

1 answer:

Ket [755]3 years ago

4 0

Answer:

{HH,CC,HC,CH}

Step-by-step explanation:

We are given that

H denotes hot and cloudy denotes C.

We have to find the total possible outcomes for the weather on two consecutive days.

The possible cases in two consecutive days

Both days are hot=HH

Both days are cloud=CC

First day is hot other day cloudy=HC

First day is cloudy other day is hot=CH

Total possible cases=HH,CC,HC,CH

Therefor, the total outcomes for the weather on two consecutive days={HH,CC,HC,CH}

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△klm, lm=20 sqrt 3 m∠k=105°, m∠m=30° find: kl and km

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Answer:

KL = $\frac{20\sqrt{6}}{1+\sqrt{3}}$ = 17.93

MK = $\frac{40\sqrt{3}}{1+\sqrt{3}}$ = 25.36

Explanation:

According to the Law of Sines:

$\frac{a}{sinA}=\frac{b}{sinB}= \frac{c}{sinC}$

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Now, we can apply the Law of Sines to our case (see picture attached):

$\frac{LM}{sinK}=\frac{MK}{sinL}=\frac{KL}{sinM}$

Let's solve one side at the time:

$\frac{LM}{sinK}=\frac{MK}{sinL}$

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$MK = \frac{20\sqrt{3} }{sin(105)} \cdot sin(45)$

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$\frac{LM}{sinK}=\frac{KL}{sinM}$

$\frac{20\sqrt{3}}{sin(105)}=\frac{KL}{sin(30)}$

$KL = \frac{20\sqrt{3} }{sin(105)} \cdot sin(30)$

KL = $\frac{20\sqrt{6}}{1+\sqrt{3}}$ = 17.93

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Read 2 more answers

Suppose we describe the weather as either hot ​(Upper H​) or cloudy ​(Upper C​). Answer parts​ (a) and​ (b) below.

Suppose we describe the weather as either hot (Upper H) or cloudy (Upper C). Answer parts (a) and (b) below.