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Nesterboy [21]
3 years ago
11

Suppose we describe the weather as either hot ​(Upper H​) or cloudy ​(Upper C​). Answer parts​ (a) and​ (b) below.

Mathematics
1 answer:
Ket [755]3 years ago
4 0

Answer:

{HH,CC,HC,CH}

Step-by-step explanation:

We are given that

H denotes hot and cloudy denotes C.

We have to find the  total possible outcomes for the weather on two consecutive days.

The possible cases in two consecutive days

Both days are hot=HH

Both days are cloud=CC

First day is hot  other day cloudy=HC

First day is cloudy other day is hot=CH

Total possible cases=HH,CC,HC,CH

Therefor, the total outcomes for the weather on two consecutive days={HH,CC,HC,CH}

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Identify the x-intercept of m(x). <br> m(x)=x^2-2x-8/x^2-x-2
SpyIntel [72]

Answer:

\large\boxed{x-intercepts:-2\ and\ 4}

Step-by-step explanation:

m(x)=\dfrac{x^2-2x-8}{x^2-x-2}\\\\\text{At the beginning we de}\text{fine the domain:}\\\\D:x^2-x-2\neq0\\\\x^2-2x+x-2\neq0\\x(x-2)+1(x-2)\neq0\\(x-2)(x+1)\neq0\iff x-2\neq0\ \wedge\ x+1\neq0\\\boxed{x\neq2\ \wedge\ x\neq-1}\\================================\\\text{The x-intercept is for}\ m(x)=0.\ \text{Therefore we have the equation:}\\\\\dfrac{x^2-2x-8}{x^2-x-2}=0\iff x^2-2x-8=0\\\\x^2+2x-4x-8=0\\x(x+2)-4(x+2)=0\\(x+2)(x-4)=0\iff x+2=0\ \vee\ x-4=0\\\\x=-2\in D\ \vee\ x=4\in D

4 0
3 years ago
What are the first four terms of the sequence an=n2+4
Igoryamba

Step-by-step explanation:

Given formula

an = n² + 4

Now the first four terms of the sequence are

a1 = 1² + 4 = 5

a2 = 2² + 4 = 4 + 4 = 8

a3 = 3² + 4 = 9 + 4 = 13

a4 = 4² + 4 = 16 + 4 = 20

The terms are

5 , 8 , 13 and 20.

7 0
3 years ago
In how many ways can we seat 3 pairs of siblings in a row of 7 chairs, so that nobody sits next to their sibling
monitta

Answer:

1,968

Step-by-step explanation:

Let x₁ and x₂, y₁ and y₂, and z₁ and z₂ represent the 3 pairs of siblings, and let;

Set X represent the set where the siblings x₁ and x₂ sit together

Set Y represent the set where the siblings y₁ and y₂ sit together

Set Z represent the set where the siblings z₁ and z₂ sit together

We have;

Where the three siblings don't sit together given as X^c∩Y^c∩Z^c

By set theory, we have;

\left | X^c \cap Y^c \cap Z^c  \right | = \left | X^c \cup Y^c \cup Z^c  \right | =  \left | U  \right | - \left | X \cup Y \cup Z  \right |

\left | U  \right | - \left | X \cup Y \cup Z  \right | = \left | U  \right | - \left (\left | X \right | +  \left | Y\right | +  \left | Z\right | -  \left | X \cap Y\right | -  \left | X \cap Z\right | -  \left | Y\cap Z\right | +  \left | X \cap Y \cap Z\right | \right)

Therefore;

\left | X^c \cap Y^c \cap Z^c  \right | = \left | U  \right | - \left (\left | X \right | +  \left | Y\right | +  \left | Z\right | -  \left | X \cap Y\right | -  \left | X \cap Z\right | -  \left | Y\cap Z\right | +  \left | X \cap Y \cap Z\right | \right)

Where;

\left | U\right | = The number of ways the 3 pairs of siblings can sit on the 7 chairs = 7!

\left | X\right | = The number of ways x₁ and x₂ can sit together on the 7 chairs = 2 × 6!

\left | Y\right | = The number of ways y₁ and y₂ can sit together on the 7 chairs = 2 × 6!

\left | Z\right | = The number of ways z₁ and z₂ can sit together on the 7 chairs = 2 × 6!

\left | X \cap Y\right | = The number of ways x₁ and x₂ and y₁ and y₂ can sit together on the 7 chairs = 2 × 2 × 5!

\left | X \cap Z\right | = The number of ways x₁ and x₂ and z₁ and z₂ can sit together on the 7 chairs = 2 × 2 × 5!

\left | Y \cap Z\right | = The number of ways y₁ and y₂ and z₁ and z₂ can sit together on the 7 chairs = 2 × 2 × 5!

\left | X \cap Y \cap Z\right | = The number of ways x₁ and x₂,  y₁ and y₂ and z₁ and z₂ can sit together on the 7 chairs = 2 × 2 × 2 × 4!

Therefore, we get;

\left | X^c \cap Y^c \cap Z^c  \right | = 7! - (2×6! + 2×6! + 2×6! - 2 × 2 × 5! - 2 × 2 × 5! - 2 × 2 × 5! + 2 × 2 × 2 × 4!)

\left | X^c \cap Y^c \cap Z^c  \right | = 5,040 - 3072 = 1,968

The number of ways where the three siblings don't sit together given as \left | X^c \cap Y^c \cap Z^c  \right |  = 1,968

5 0
3 years ago
How do you find the value of n in a geometric progression?​
Bas_tet [7]

A geometric progression is also known as a geometric sequence.

Here is a video explaining how you find the n term value.

https://youtu.be/pwUdYEwT9kY

Hope this helps!

6 0
3 years ago
Juan bought n packs of pencils. Each pack has 15 Write an equation to represent the total number of pencils p that Juan bought.
pav-90 [236]

Answer:

15*n=p

Step-by-step explanation:

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3 years ago
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