Answer:
33
Step-by-step explanation:
You can calculate the distance between two point using this fomula:
√(x_2-x_1)^2+(y_2-y_1)^2
If you insert you values you get:
√(4-5)^2+(-7-2)^2 = 9.06 = 9.1
Answer:
10x² + 6x + 3xy + 3y - y²
Step-by-step explanation:
Each term in the second factor is multiplied by each term in the first factor, as shown
(2x + y)(5x - y + 3)
= 2x(5x - y + 3) + y(5x - y + 3) ← distributing
= 10x² - 2xy + 6x + 5xy - y² + 3y ( collect like terms )
= 10x² + 6x + 3xy + 3y - y²
Let 1st integer = xLet 2nd integer = x + 1 We set up an equation. x(x + 1) = 195 x2 + x = 195 x2 + x - 195 = 0
We will use the quadratic formula: x = (-b ± √(b2 - 4ac) / (2a) x = (-1 ± √(1 - 4(-195))) / 2 x = (-1 ± √(781)) / 2 x = (-1 ± 27.95) / 2 x = 13.48x = -14.78
<span>We determine which value of x when substituted gives us a product of 195.</span> 13.48(14.48) = 195.19-14.48(-13.48) = 195.19 <span>The solution is 2 sets of two consecutive number</span> <span>Set 1</span> The 1st consecutive integer is 13.48The 2nd consecutive integer is 14.48
<span>Set 2</span> The 1st consecutive integer is -14.48The 2nd consecutive integer is -13.48Hopefully this helped, hard work lol :)
Answer:
the answer is on photomath