Integrate indefinite integral:
Solution:
1. use substitution
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2. decompose into partial fractions
where A=1/2, B=1/2, C=-1
3. Substitute partial fractions and continue
4. back-substitute u=e^x
Note: log(x) stands for natural log, and NOT log10(x)
Answer:
D=2/27
Step-by-step explanation:
D/(1/6)=4/9
D/(1/6) x (1/6)=(4/9) x (1/6)
D=4/54
D=2/27
Answer: 33
Explanation: The last number is one less than double the previous number.
Hope that helps! Have a good day :)
1)
x^2 + 4 = 0 Subtract 4 from each side
x^2 = -4
You cannot square a number to get a negative number. No real solution. (If you have learned about imaginary numbers, answer is 2i)
2)
<span>x^2+x-6=0 Factor. 3 and -2 add up to 1, and multiply to -6
(x+3)(x-2) = 0
Zero Product Property: Which numbers would put a zero in one of the parentheses?
x = -3 or x=2
3) </span><span>x^2-6x+7=0
Completing the Square:
Take half of b (-6), square it, and add/subtract that coefficient
x^2 - 6x + 9 - 9 + 7 = 0
(x -3)^2 - 2 = 0 Add 2 to both sides
(x-3)^2</span> = 2 Take the square root of both sides
<span>(x-3) = </span>√2 or -√2 Add 3 to both sides
<span>x = 3 + </span>√2 or 3 - √2<span>
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