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Nata [24]
3 years ago
6

14. A plane traveled from California and back. It took one hour longer on the way out than it did on the way back. The plane's a

verage
speed out was 300 mph. The average speed on the way back was 350 mph. How many hours did the trip out take?
A. 13 hours
B. 8 hours
C. 7 hours
D. 6 hours
Mathematics
1 answer:
kow [346]3 years ago
8 0

Answer:

  C.  7 hours

Step-by-step explanation:

Let the time for the trip out be represented by t. Then the time for the return trip is t-1. The distance was the same for both trips, so we have ...

  distance = speed × time

  300t = 350(t -1)

  300t = 350t -350 . . . . eliminate parentheses

  350 = 50t . . . . . . . . . . add 350-300t

  7 = t . . . . . . divide by 50

The trip out took 7 hours.

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<h2>Answer:</h2>

f^{-1}  (x)=\sqrt{\frac{x}{14}}.

<h2>Step-by-step explanation:</h2>

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<h3>2. Substitute y for x, and x for y.</h3>

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<h3>4. Express your result.</h3>

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