Question

14. A plane traveled from California and back. It took one hour longer on the way out than it did on the way back. The plane's average
speed out was 300 mph. The average speed on the way back was 350 mph. How many hours did the trip out take?
A. 13 hours
B. 8 hours
C. 7 hours
D. 6 hours

Answer 1

Answer:

  C.  7 hours

Step-by-step explanation:

Let the time for the trip out be represented by t. Then the time for the return trip is t-1. The distance was the same for both trips, so we have ...

  distance = speed × time

  300t = 350(t -1)

  300t = 350t -350 . . . . eliminate parentheses

  350 = 50t . . . . . . . . . . add 350-300t

  7 = t . . . . . . divide by 50

The trip out took 7 hours.