14. A plane traveled from California and back. It took one hour longer on the way out than it did on the way back. The plane's a

Question

3 years ago

6

14. A plane traveled from California and back. It took one hour longer on the way out than it did on the way back. The plane's a

verage
speed out was 300 mph. The average speed on the way back was 350 mph. How many hours did the trip out take?
A. 13 hours
B. 8 hours
C. 7 hours
D. 6 hours

Mathematics

1 answer:

kow [346] · Answer 1 · 2022-03-18T21:26:20+03:00

Answer:

C. 7 hours

Step-by-step explanation:

Let the time for the trip out be represented by t. Then the time for the return trip is t-1. The distance was the same for both trips, so we have ...

distance = speed × time

300t = 350(t -1)

300t = 350t -350 . . . . eliminate parentheses

350 = 50t . . . . . . . . . . add 350-300t

7 = t . . . . . . divide by 50

The trip out took 7 hours.