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Talja [164]
4 years ago
10

The function h(x)=1/x^2+1 is the result of the composition f(g(x)). If g(x) = x^2+1,what is f(x)? A f(x)=1/square root x B f(x)=

1/x C f(x)= 1/x+1 D f(x)=1/x^2+1
Mathematics
1 answer:
HACTEHA [7]4 years ago
3 0

Answer:

Option B is correct

Step-by-step explanation:

Given: h(x)=\frac{1}{x^2+1} is the result of the composition f(g(x)).

Also, g(x)=x^2+1

To find: f(x)

Solution:

Take f(x)=\frac{1}{x}

Now check whether h(x) is equal to f(g(x)) or not.

First find f(g(x))

f(g(x))=f(x^2+1)=\frac{1}{x^2+1}

Also, h(x)=\frac{1}{x^2+1}

Therefore,

h(x)=f(g(x))

So,

Option B is correct

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Which number is an irrational number
12345 [234]

Answer:

A choice.

Step-by-step explanation:

Irrational number is a number that cannot be written in a fraction form. All square roots are classified as an Irrational number unless can be evaluated to Rational number.

From A choice, you cannot evaluate the square root of 7 into any rational number. Therefore, it is an Irrational number.

B choice, even though there is a square root, but you can still evaluate from square root of 4 to 2.

For C and D, both are integers. Integers are classified to be Rational Number. Therefore, C and D both are rational.

7 0
3 years ago
Combine like terms and classify the polynomial by the number of terms.
andriy [413]

The answer is C. Binomial

8 0
2 years ago
Read 2 more answers
What are one dimensional figures
agasfer [191]
Hello!

In geometry there are three dimensions.

Something that is one dimensional is neither flat, wide, or tall. It is just a line.
——————————————
Something two dimensional is flat and wide but has no height. An example of this is a square.

Something three dimensional is wide and tall, and has flat faces. An example is a cube.

To answer your question something one dimensional is something that is not flat, wide, or tall, such as a line.

Hope this helped!
3 0
3 years ago
A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On
anastassius [24]

Given:

The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

h(x)=ax(x-7)             ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

4=a(3)((3)-7)

4=a(3)(-4)

\dfrac{4}{(3)(-4)}=a

-\dfrac{1}{3}=a

Putting a=-\dfrac{1}{3}, we get

h(x)=-\dfrac{1}{3}x(x-7)              ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)

h(1.5)=-(0.5)(-5.5)

h(1.5)=2.75

It is clear that h(1.5)<2.8, therefore the trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is not possible.

4 0
3 years ago
CAN someone help pweaseeee ill mark brainliest
zepelin [54]

Answer:

a.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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