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Talja [164]
4 years ago
10

The function h(x)=1/x^2+1 is the result of the composition f(g(x)). If g(x) = x^2+1,what is f(x)? A f(x)=1/square root x B f(x)=

1/x C f(x)= 1/x+1 D f(x)=1/x^2+1
Mathematics
1 answer:
HACTEHA [7]4 years ago
3 0

Answer:

Option B is correct

Step-by-step explanation:

Given: h(x)=\frac{1}{x^2+1} is the result of the composition f(g(x)).

Also, g(x)=x^2+1

To find: f(x)

Solution:

Take f(x)=\frac{1}{x}

Now check whether h(x) is equal to f(g(x)) or not.

First find f(g(x))

f(g(x))=f(x^2+1)=\frac{1}{x^2+1}

Also, h(x)=\frac{1}{x^2+1}

Therefore,

h(x)=f(g(x))

So,

Option B is correct

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If you know how to add and subtract whole numbers, then you can add and subtract decimals! Just be sure to line up the terms so that all the decimal points are in a vertical line.
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Put the numbers in a vertical column, aligning the decimal points
Add each column of digits, starting on the right and working left. If the sum of a column is more than ten, "carry" digits to the next column on the left.
Place the decimal point in the answer directly below the decimal points in the terms.
To subtract decimal numbers:

Put the numbers in a vertical column, aligning the decimal points.
Subtract each column, starting on the right and working left. If the digit being subtracted in a column is larger than the digit above it, "borrow" a digit from the next column to the left.
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To add these numbers, first arrange the terms vertically, aligning the decimal points in each term. Don't forget, for a whole number like the first term, the decimal point lies just to the right of the ones column. You can add zeroes to the right of the decimal point to make it easier to align the columns. Then add the columns working from the right to the left, positioning the decimal point in the answer directly under the decimal points in.

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· Place value

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4 years ago
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scZoUnD [109]
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3 years ago
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LekaFEV [45]

Answer:

see explanation

Step-by-step explanation:

(a)

Given

2k - 6k² + 4k³ ← factor out 2k from each term

= 2k(1 - 3k + 2k²)

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Consider the factors of the product of the constant term ( 1) and the coefficient of the k² term (+ 2) which sum to give the coefficient of the k- term (- 3)

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Use these factors to split the k- term

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(b)

Given

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= 2a(x - 2y) + 3b(x - 2y) ← factor out (x - 2y) from each term

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