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oksano4ka [1.4K]
3 years ago
6

Can someone pls help me

Mathematics
1 answer:
MAVERICK [17]3 years ago
6 0
Standard deviation I think
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C is the midpoint of bc, bc = 7 and CD = 3x- 5 what is the value of x
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What is the value of D? In order to solve, you need to find all the variable values to solve for x.
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What is the range of f?
zhannawk [14.2K]

Answer: [-3,7]

Step-by-step explanation:

The range of a function is the set of y-values

4 0
2 years ago
Police estimate that​ 25% of drivers drive without their seat belts. If they stop 6 drivers at​ random, find the probability tha
Furkat [3]

Answer:

17.80% probability that all of them are wearing their seat belts.

Step-by-step explanation:

For each driver stopped, there are only two possible outcomes. Either they are wearing their seatbelts, or they are not. The drivers are chosen at random, which mean that the probability of a driver wearing their seatbelts is independent from other drivers. So we use the normal probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Police estimate that​ 25% of drivers drive without their seat belts.

This means that 75% wear their seatbelts, so p = 0.75

If they stop 6 drivers at​ random, find the probability that all of them are wearing their seat belts.

This is P(X = 6).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{6,6}.(0.75)^{6}.(0.25)^{0} = 0.1780

17.80% probability that all of them are wearing their seat belts.

3 0
3 years ago
Read 2 more answers
D2 =81-1 find the positive value of d that makes the equation true
Lubov Fominskaja [6]
81-1= 80
80 / 2 = 40
D = 40
So:
40(2) = 81 - 1
4 0
3 years ago
Type the correct answer in each box. If necessary, use /for the fraction bars
Vikentia [17]

Answer:

The experimental probability of rolling an odd number is 60%, which is 10% more than the theoretical probability.

Step-by-step explanation:

The complete question is:

Type the correct answer in each box. Use numerals instead of words. If necessary, use/ for the fraction bar(s).

A special 8-sided die is marked with the numbers 1 to 8. It is rolled 20 times with these outcomes.

3, 4, 5, 2, 7, 1, 3, 7, 2, 6, 2, 1, 7, 3, 6, 1, 8, 3, 5, 6

The experimental probability of rolling an odd number is _%, which is _% more than the theoretical probability.

Solution:

The possible outcomes of rolling an 8-sided die are:

S = {1, 2, 3, 4, 5, 6, 7, 8}

The odd numbers are:

Odd = {1, 3, 5, 7} = 4 outcomes

The theoretical probability of rolling an odd number is:

P_{T}(\text{Odd})=\farc{4}{8}=\frac{1}{2}=50\%

Now from the given 20 outcomes the odd values are:

Odd = {3, 5, 7, 1, 3, 7, 1, 7, 3, 1, 3, 5} = 12 outcomes

Compute the experimental probability of rolling an odd number as follows:

P_{E}(\text{Odd})=\frac{12}{20}=\frac{3}{5}=60\%

Thus, the experimental probability of rolling an odd number is 60%, which is 10% more than the theoretical probability.

6 0
2 years ago
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