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DaniilM [7]
3 years ago
14

A train travels from station A to station B. If the train leaves station A and makes 75 km/hr, it arrives at station B 48 minute

s ahead of scheduled. If it made 50 km/hr, then by the scheduled time of arrival it would still have 40 km more to go to station B. Find:
A) The distance between the two stations;
B) The time it takes the train to travel from A to B according to the schedule;
C) The speed of the train when it's on schedule.
Mathematics
1 answer:
SSSSS [86.1K]3 years ago
6 0

Answer:

  • A) 290 km
  • B) 4 hours
  • C) 72.5 km/h

Step-by-step explanation:

Let distance be d and time t

<u>At 75 km/h speed the distance is</u>

  • d = 75(t - 48 min) = 75(t - 48/60 hours)

<u>At 50 km/h speed the distance</u> is

  • d = 50t + 40

<u>Since the distance is same, we get the equation:</u>

  • 75(t - 48/60) = 50t + 40
  • 75t - 75*4/5 = 50t + 40
  • 75t - 60 = 50t + 40
  • 75t - 50t = 40 + 60
  • 25t = 100
  • t = 4 hours

<u>A) The distance between A and B</u>

  • d = 50*5 + 40 = 290 km

<u>B) Time is </u>

  • 4 hours as found above

<u>C) The speed = d/t</u>

  • Speed = 290/4 = 72.5 km/h

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I understand that the question you are looking for is:

Russ is solving an equation where both sides are linear expressions. He sets the expressions equal to y and graphs the system finding that they are the same line. How should Russ interpret this outcome? There are no intersection points. There is exactly one intersection point. There are exactly two intersection points. There are infinitely many intersection points.Russ is solving an equation where both sides are linear expressions. He sets the expressions equal to y and graphs the system finding that they are the same line. How should Russ interpret this outcome?

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