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Luba_88 [7]
3 years ago
8

What is 2• 2 • 2• 2• 2•2

Mathematics
2 answers:
yaroslaw [1]3 years ago
3 0

Answer:

64

Step-by-step explanation:

2 x 2=4

4x 2= 8

8 x 2= 16

16 x 2=32

32 x 2= 64

jasenka [17]3 years ago
3 0

Answer:

64

Step-by-step explanation:

2 * 2 * 2 * 2 * 2 * 2 = 2 ^ 6

                               = 64

Hope this answer helped you!!

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Ket [755]

I would guess it would be letter B. Let me know if I’m right.

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2 years ago
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A sled is being held at rest on a slope that makes an angle theta with the horizontal. After the sled is released, it slides a d
Alenkasestr [34]

Answer:

μ =  Sin θ * d₁ / (d₂ - Cos θ*d₁)

d₂ = (d₁*Sin θ) / μ

Step-by-step explanation:

a) We apply The work-energy theorem

W = ΔE

W = - Ff*d

Ff = μ*N = μ*m*g

<em>Distance 1:</em>

- Ff*d₁ = Ef - Ei

⇒  - (μ*m*g*Cos θ)*d₁ = (Kf+Uf) - (Ki+Ui) = (Kf+0) - (0+Ui) = Kf - Ui

Kf = 0.5*m*vf² = 0.5*m*v²

Ui = m*g*h = m*g*d₁*Sin θ

then

- (μ*m*g*Cos θ)*d₁ = 0.5*m*v² - m*g*d₁*Sin θ  

⇒   - μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ   <em>(I)</em>

 

<em>Distance 2:</em>

<em />

- Ff*d₂ = Ef - Ei

⇒  - (μ*m*g)*d₂ = (0+0) - (Ki+0) = - Ki

Ki = 0.5*m*vi² = 0.5*m*v²

then

- (μ*m*g)*d₂ = - 0.5*m*v²

⇒   μ*g*d₂ = 0.5*v²     <em>(II)</em>

<em />

<em>If we apply (I) + (II)</em>

- μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ

μ*g*d₂ = 0.5*v²

 ⇒ μ*g (d₂ - Cos θ*d₁) = v² - g*d₁*Sin θ   <em>  (III)</em>

Applying the equation (for the distance 1) we get v:

vf² = vi² + 2*a*d = 0² + 2*(g*Sin θ)*d₁   ⇒   vf² = 2*g*Sin θ*d₁ = v²

then (from the equation <em>III</em>) we get

μ*g (d₂ - Cos θ*d₁) = 2*g*Sin θ*d₁ - g*d₁*Sin θ

⇒  μ (d₂ - Cos θ*d₁) = Sin θ * d₁

⇒   μ =  Sin θ * d₁ / (d₂ - Cos θ*d₁)

b)

If μ is a known value

d₂ = ?

We apply The work-energy theorem again

W = ΔK   ⇒   - Ff*d₂ = Kf - Ki

Ff = μ*m*g

Kf = 0

Ki = 0.5*m*v² = 0.5*m*2*g*Sin θ*d₁ = m*g*Sin θ*d₁

Finally

- μ*m*g*d₂ = 0 - m*g*Sin θ*d₁   ⇒   d₂ = Sin θ*d₁ / μ

3 0
3 years ago
Which statement is correct? A) 13/ 3 &lt; 4.25 &lt; 43 /10 B) 43 /10 &lt; 13 /3 &lt; 4.25 C) 4.25 &lt; 13 /3 &lt; 43/ 10 D) 4.25
Ivan
D. 4.25 < 43/10 < 13/3 
     
4.25   = 4.25
43/10 = 4.3
13/3   = 4.33

4.25 < 4.3 < 4.33
4 0
3 years ago
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I need help what’s the answer ?
pogonyaev

Answer:

x = 30

Step-by-step explanation:

Using the sine ratio in the right triangle

sinx = \frac{opposite}{hypotenuse} = \frac{2.5}{5} = \frac{1}{2} , then

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Benjamin writes an expression for the sum of 1 cubed, 2 cubed and 3 cubed. What is the value at the expression
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Answer:

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Step-by-step explanation:

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