Let s represent the length of any one side of the original square. The longer side of the resulting rectangle is s + 9 and the shorter side s - 2.
The area of this rectangle is (s+9)(s-2) = 60 in^2.
This is a quadratic equation and can be solved using various methods. Let's rewrite this equation in standard form: s^2 + 7s - 18 = 60, or:
s^2 + 7s - 78 = 0. This factors as follows: (s+13)(s-6)=0, so that s = -13 and s= 6. Discard s = -13, since the side length cannot be negative. Then s = 6, and the area of the original square was 36 in^2.
Answer:
{ y = 3x + 3
{ 3x - y = 3
B
(Just did the assignment 3/23/21)
Answer:
(
−
2
)
=
−
1
4
(
−
8
)
(x-2)=\frac{-1}{4}(x-8)
(x−2)=4−1(x−8)
Solve
1
Eliminate redundant parentheses
(
−
2
)
=
−
1
4
(
−
8
)
−
2
=
−
1
4
(
−
8
)
2
Combine multiplied terms into a single fraction
−
2
=
−
1
4
(
−
8
)
−
2
=
−
1
(
−
8
)
4
3
Distribute
−
2
=
−
1
(
−
8
)
4
−
2
=
−
+
8
4
4
Add
2
2
2
to both sides of the equation
−
2
=
−
+
8
4
−
2
+
2
=
−
+
8
4
+
2
5
Simplify
Add the numbers
=
−
+
8
4
+
2
Solution
=
1
6
5
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given
--- right angle
Required
Which of the options is true
In a triangle, we have:
--- angles in a triangle
Substitute
Collect like terms
This implies that E and G are complementary angles.
For complementary angles, E and G;
and 
<em>Hence, (4) is true</em>
