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defon
3 years ago
8

Find the value of x. :]]

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
6 0

Answer:

144

Step-by-step explanation:

True [87]3 years ago
5 0

Answer:

54

Step-by-step explanation:

This is a right angle (complementary angles) so 90-43 is 47 and the angel is x - 7 so you have to add 7. Answer is 54 <3

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BRAINLIEST!! HELP!!
atroni [7]

Definition of midpoint.

<K is midpoint for all, hence its reference.

5 0
4 years ago
Please me<br><br>please me noww​
vesna_86 [32]

Step-by-step explanation:

5. answer ➡D

6 . answer ➡A

8 . answer ➡C

3 0
4 years ago
Read 2 more answers
Field book of an land is given in the figure. It is divided into 4 plots . Plot I is a right triangle , plot II is an equilatera
Kazeer [188]

Answer:

Total area = 237.09 cm²

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)

From the figure attached,

Area of the right triangle I = \frac{1}{2}(\text{Base})\times (\text{Height})

Area of ΔADC = \frac{1}{2}(\text{CD})(\text{AD})

                        = \frac{1}{2}(\sqrt{(AC)^2-(AD)^2})(\text{AD})

                        = \frac{1}{2}(\sqrt{(13)^2-(19-7)^2} )(19-7)

                        = \frac{1}{2}(\sqrt{169-144})(12)

                        = \frac{1}{2}(5)(12)

                        = 30 cm²

Area of equilateral triangle II = \frac{\sqrt{3} }{4}(\text{Side})^2

Area of equilateral triangle II = \frac{\sqrt{3}}{4}(13)^2

                                                = \frac{(1.73)(169)}{4}

                                                = 73.0925

                                                ≈ 73.09 cm²

Area of rectangle III = Length × width

                                 = CF × CD

                                 = 7 × 5

                                 = 35 cm²

Area of trapezium EFGH = \frac{1}{2}(\text{EF}+\text{GH})(\text{FJ})

Since, GH = GJ + JK + KH

17 = \sqrt{9^{2}-x^{2}}+5+\sqrt{(15)^2-x^{2}}

12 = \sqrt{81-x^2}+\sqrt{225-x^2}

144 = (81 - x²) + (225 - x²) + 2\sqrt{(81-x^2)(225-x^2)}

144 - 306 = -2x² + 2\sqrt{(81-x^2)(225-x^2)}

-81 = -x² + \sqrt{(81-x^2)(225-x^2)}

(x² - 81)² = (81 - x²)(225 - x²)

x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴

144x² - 11664 = 0

x² = 81

x = 9 cm

Now area of plot IV = \frac{1}{2}(5+17)(9)

                                = 99 cm²

Total Area of the land = 30 + 73.09 + 35 + 99

                                    = 237.09 cm²

7 0
3 years ago
I need help simplifying both of these. thank you!
4vir4ik [10]
<h3>Answer:</h3>
  1. -100x +100; 3
  2. 5x +81; 162
<h3>Step-by-step explanation:</h3>

The distributive property is your friend. It tells you ...

  a(b + c) = ab + ac

It can also be used to simplify the product of binomials (or other polynomials).

  (a +b)^2 = (a +b)(a +b) = a(a +b) + b(a +b) = a^2 +ab +ab +b^2

  (a +b)^2 = a^2 +2ab + b^2 . . . . . . . worth remembering

1. (x -10)^2 -x(x +80) = (x^2 -20x +100) +(-x^2 -80x)

  = -100x +100 . . . . . . simplified form

For the purposes of calculation, it can be easier to factor out 100:

  = 100 (1 -x)

Then for x = 0.97

  = 100(1 -0.97) = 100(0.03) = 3

___

2. (2x +9)^2 -x(4x +31) = (4x^2 +36x +81) -4x^2 -31x = 5x +81

For x = 16.2, this is ...

  5(16.2) +81 = 81 +81 = 162

_____

The purpose of the attachment is to show the evaluation is correct.

5 0
3 years ago
PLEASE HURRY WILL MARK BRAINIEST THIS IS AN EASY QUESTION
viva [34]

first qn

4/36=1/9

total no. of ways to roll a dice=36

no. of ways to produce 7=3

(1+6=7, 2+5=7, 3+4=7)

no. of ways to produce 11=1

(5+6=11)

there are 4 ways in total. 4/36 simplify it to be 1/9

second qn im not sure but i think its

1/9 x 50 = 50/9 = 5 x (5/9)

round it off to the smaller whole no. which is 5 so i think its 5 times in 50 trials

7 0
3 years ago
Read 2 more answers
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