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3 years ago

14

Simplify to create an equivalent expression. 8−4(−x+5)

1 answer:

White raven [17]3 years ago

3 0

8 - 4(-x + 5)

As you already know, in order to find the equivalent expression to our already given one, we have to simplify it first :)

8 +4x - 20

**Remember that a negative times a negative is always a positive!!**

Add like terms.

4x + (8 - 20)

Simplify.

4x + (-12)

Get rid of parenthesis.

4x - 12

Look at our answer choices.

Our answer is a. 4x - 12

~Hope I helped!~

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A train is traveling at a constant speed. The table shows the distance the train travels at different times during the trip. How

SpyIntel [72]

The train is traveling at 165 mph

495/3=165
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3 years ago

Consider the sequence whose first five terms are shown. -59 ,-67 ,-65 ,-53 ,-31 ,... The first term is ____ To calculate the sec

GaryK [48]

Step-by-step explanation:

The sequence is as follows :

-59 ,-67 ,-65 ,-53 ,-31 ,...

The first term = -59

The second term = -67

Common difference = second term - first term

$=-67-(-59)\\\\=-8$

To calculate the second term add (-8).

To calculate each additional term, increase the amount added by -8.

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3 years ago

If 5 + 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline + 5, what is the value of x? –

sp2606 [1]

Answer:

<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>

Step-by-step explanation:

Given equation is $5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

<h3>To find the value of x :</h3>

First solving the given equation we have,

$5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

$5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5$

$20\times (2)^{2-3x}=10\times (2)^{-2x}$

$20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}$

$20\times 4.(2)^{-3x}=10\times (2)^{-2x}$

$80(2)^{-3x}=10\times (2)^{-2x}$

$\frac{80}{10}(2)^{-3x}=\frac{10\times (2)^{-2x}}{10}$

$8(2)^{-3x}=(2)^{-2x}$

$\frac{(2)^{-3x}}{(2)^{-2x}}=\frac{1}{8}$

$(2)^{-3x}.(2)^{2x}=\frac{1}{2^3}$ ( by using the property $\frac{1}{a^{-m}}=a^m$ )

$2^{-3x+2x}=\frac{1}{2^3}$ ( by using the property $a^m.a^n=a^{m+n}$ )

$2^{-x}=\frac{1}{2^3}$

$\frac{1}{2^x}=\frac{1}{2^3}$ ( by using the property $a^{-m}=\frac{1}{a^m}$ )

Since bases are same so powers are same

Therefore we can equate the powers we get x=3

<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>

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zaharov [31]

Answer:

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Step-by-step explanation:

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