We have been given that Judy’s brother Sam has a collection of 96 comic books.
We have been asked to find the 10 ways Sam could divide his comic books into equal groups.
This can be done as follows:
96 can be written as .
Thus, we can either have 2 groups of 48 comics or 48 groups of 2 comics. As we can see we have 2 ways to divide the comic books in equal groups.
Likewise, 96 can also be written as . Here, we can similarly see that we can either have 3 groups of 32 comics or 32 groups of 3 comics. As we can again see we have 2 more ways to divide the comic books in equal groups, taking the total number of ways to 4.
Continuing in this manner we will see that we can have 4 groups of 24 or 24 groups of 4, 6 groups of 16 or 16 groups of 6 and lastly 12 groups of 8 or 8 groups of 12 comic books, thus taking the count to a total of 10 ways in which Sam can divide his comic books into equal groups.
FAXT
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Answer:
9+10 =19
Step-by-step explanation:is that wat u wanted
Answer:
The only point (0,0) lies inside the shaded region and hence it gives a solution for the set of inequalities.
Step-by-step explanation:
See the graph attached to this question.
The solution of the set of inequalities is given by the shaded region on the graph.
Now, the point (0,5) is outside this shaded region, hence it can not be the solution.
The point (3,0) also is outside this shaded region, hence it can not be the solution.
The point (-3,0) also is outside this shaded region, hence it can not be the solution.
Now, the only point (0,0) lies inside the shaded region and hence it gives a solution for the set of inequalities. (Answer)
Answer:
D. Class frequency divided by the total frequency.
