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Mashutka [201]
3 years ago
12

How do I use the Descartes Rule of Signs to determine all possible number of positive and negative zeros?

Mathematics
1 answer:
larisa [96]3 years ago
8 0

Answer:

We conclude that:

  • 2  or 0 positive real roots
  • 2  or 0 negative real roots

Step-by-step explanation:

Descartes Rule states that if the terms of a single-variable polynomial with real coefficients are ordered by descending variable exponent, then the number of positive roots of the polynomial is:

  • Either equal to the number of sign differences between consecutive nonzero coefficients,
  • Or is less than it by an even number.

Given the function

f\left(x\right)=x^4-2x^3-4x^2+2x+3

So, the coefficients are 1, −2, −4, 2, 3

As can be seen, there are 2 changes.

This means that there are 2 or 0 positive real roots.

To find the number of negative real roots, substitute x with -x in the given polynomial:

x^4-2x^3-4x^2+2x+3  becomes x^4+2x^3-4x^2-2x+3

The coefficients are 1, 2, −4, −2, 3

As can be seen, there are 2 changes.

This means that there are 2 or 0 negative real roots.

Therefore, we conclude that:

  • 2  or 0 positive real roots
  • 2  or 0 negative real roots

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A union of restaurant and foodservice workers would like to estimate the mean hourly wage, μ, of foodservice workers in the U.S.
pav-90 [236]

Answer:

n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159

So the answer for this case would be n=159 rounded up to the nearest integer

Step-by-step explanation:

Assuming this complete question: A union of restaurant and foodservice workers would like to estimate the mean hourly wage, , of foodservice workers in the U.S. The union will choose a random sample of wages and then estimate using the mean of the sample. What is the minimum sample size needed in order for the union to be 95% confident that its estimate is within $0.35 of ? Suppose that the standard deviation of wages of foodservice workers in the U.S. is about $2.15 .

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=2.25 represent the population standard deviation

n represent the sample size  

Solution to the problem

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

And on this case we have that ME =0.35 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159

So the answer for this case would be n=159 rounded up to the nearest integer

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Which is greater 9,000cm or 2 km
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The 2 km is bigger than 9,000 cm because the 9,000 will equal 0.09 in km
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