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4vir4ik [10]
3 years ago
15

Can someone help me please

Mathematics
1 answer:
Bumek [7]3 years ago
4 0

Answer:

yes what would u like help with

You might be interested in
Please I need help it's really hard
Vitek1552 [10]
I'd say angle A = angle B
arc tangent (angle B) = 150 / 555
<span><span><span>arc tangent (angle B) = 0.2702702703 </span>
angle B = 15.124 degrees

By the way 555 feet is the height of the Washington Monument.
</span> </span>
3 0
3 years ago
What is the circumference of the following circle?<br> 9 cm
liq [111]

Answer:

9π or 28.27 cm

Step-by-step explanation:

The circumference formula is 2πr or dπ. The diameter is 9 cm so we multiply 9 with pi to get the answer.

7 0
3 years ago
Work out the acceleration for the first 3 seconds?
Finger [1]

The acceleration is given by the slope of the line. This line passes through the points (0, 2) and (3, 5), so it has slope

\dfrac{5-2}{3-0}=1

which means the acceleration over this 3 second interval is 1 m/s^2.

5 0
3 years ago
Read 2 more answers
A local car dealer claims that 25% of all cars in San Francisco are blue. You take a random sample of 600 cars in San Francisco
sammy [17]

Answer:

No, we can't reject the dealer's claim with a significance level of 0.05.

Step-by-step explanation:

We are given that a local car dealer claims that 25% of all cars in San Francisco are blue.

You take a random sample of 600 cars in San Francisco and find that 141 are blue.

<u><em>Let p = proportion of all cars in San Francisco who are blue</em></u>

SO, Null Hypothesis, H_0 : p = 25%   {means that 25% of all cars in San Francisco are blue}

Alternate Hypothesis, H_A : p \neq 25%   {means that % of all cars in San Francisco who are blue is different from 25%}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 600 cars in San Francisco who are blue =   \frac{141}{600} = 0.235

            n = sample of cars = 600

So, <u><em>test statistics</em></u>  =  \frac{0.235-0.25}{{\sqrt{\frac{0.235(1-0.235)}{600} } } } }

                               =  -0.866

<em>Now at 0.05 significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics lies within the range of critical values of z so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that 25% of all cars in San Francisco are blue which means the dealer's claim was correct.

4 0
3 years ago
Please answer as soon as possible. Due by 11:59
Basile [38]
15x+40=-47+27
15x+40=-20
15x=-60
X=-4
8 0
3 years ago
Read 2 more answers
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