It is.........................................................
Step-by-step explanation:
first you have to solve for x
35x - 5=50
35-35x-5= 50-35
x-5=15
x- 5÷5=15÷5
x=3
Now we have to substitute x into the equation.
35×(3)-5=
175-5=170
angle UVW= 170
to find angle HUW instead of solving the equation just subtract 170 from 50 and you will get 120.
angle UVH=50
angle HUW=120
angle UVW=170
I hope this helps srry it took so long but gn and gl.
Answer:
A) 34.13%
B) 15.87%
C) 95.44%
D) 97.72%
E) 49.87%
F) 0.13%
Step-by-step explanation:
To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:
Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:
So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:
P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)
= 0.5 - 0.1587 = 0.3413
It means that the PERCENT of scores that are between 90 and 100 is 34.13%
At the same way, we can calculated the percentages of B, C, D, E and F as:
B) Over 110
C) Between 80 and 120
D) less than 80
E) Between 70 and 100
F) More than 130
First step find a common multiple, e.g. 45 and subtract
9x + 5y = 28 * 5
5x + 9y = 56 * 9
45x + 25y = 140
-(45x + 81y = 504)
-56y = -364
56y = 364
y = 6.5
Substitute into any equation
9x + 5(6.5) = 28
9x + 32.5 = 28
9x = -4.5
x = -0.5
x = -0.5 , y = 6.5