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2 years ago

Solve V = 1/3πr2h for h.

Mathematics

1 answer:

Rashid [163]2 years ago

7 0

Step-by-step explanation:

v=1/3nr2h for h

3(v)=3(1/3nr2h)

3v/2nrh=2nrh/2nr

3v/2nrh=h

h = 3v/2nrh

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1) Omar has scored 85, 71, and 77 on the first three exams in his math class. If the standard 70,80,90 scale is used for grades

Rus_ich [418]

Answer:

a. 47

b. 87

c. 127

Step-by-step explanation:

Assume a total of 4 exams ( first 3 plus a final)

Let final score be X,

Hence, average score = (85 + 71 + 77 + x) / 4 = (233 + x) / 4

a) to get a C, the average score must be 70

70 = (233 + x) / 4

(233 + x) = 70 (4) = 280

x = 280 - 233 = 47 (Ans)

b) to get a B, the average score must be 80

80 = (233 + x) / 4

(233 + x) = 80 (4) = 320

x = 320 - 233 = 87 (Ans)

c) to get a A, the average score must be 90

90 = (233 + x) / 4

(233 + x) = 90 (4) = 360

x = 360 - 233 = 127 (Ans)

6 0

2 years ago

The table represents a linear function. <br><br> What is the slope of the function?

otez555 [7]

Answer:

-6

Step-by-step explanation:

The slope of a line is given with the formula

$m=\frac{y_2-y_1}{x_2-x_1}$

Using the first two points, (-2, 8) and (-1, 2), we have

m = (2-8)/(-1--2) = -6/(-1+2) = -6/1 = -6

4 0

2 years ago

Read 2 more answers

Zoe jogs 3/4 of a mile every 1/5 of an hour.

stepan [7]

Answer:

15/4 please let me know if this helped you :)

Step-by-step explanation:

0.75*5=3.75 or 15/4

all of your answers are less than 3/4ths of a mile...she is increasing the amount she runs not decreasing.

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2 years ago

) Find AD if BC = 13x + 279.<br>AD = 2x + 135, AC = 11x + 267,<br>and BD = 63.

Cloud [144]

Answer:

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Step-by-step explanation:

erw

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2 years ago

A company wants to establish that the mean life of its batteries, when used in a wireless mouse, is over 183 days. The data will

enyata [817]

Answer:

a) Null and alternative hypotheses are:

$H_{0}$ : mu=183 days

$H_{a}$ : mu>183 days

b) If the true mean is 190 days, Type II error can be made.

Step-by-step explanation:

Let mu be the mean life of the batteries of the company when it is used in a wireless mouse

Null and alternative hypotheses are:

$H_{0}$ : mu=183 days

$H_{a}$ : mu>183 days

Type II error happens if we fail to reject the null hypothesis, when actually the alternative hypothesis is true.

That is if we conclude that mean life of the batteries of the company when it is used in a wireless mouse is at most 183 days, but actually mean life is 190 hours, we make a Type II error.

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3 years ago