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2 years ago

Solve the equation Y +3 = -y + 9

Mathematics

2 answers:

statuscvo [17]2 years ago

5 0

Answer:

y=3

Step-by-step explanation:

Regroup terms.

y+3=9-y

Subtract 3 from both sides.

y=9-y-3

Simplify 9-y-3 to 6-y

y=6-y

Add y to both sides.

y+y=6

Simplify y+y to 2y.

2y=6

Divide both sides by 2.

y= 6/2

then the answer is y=3

sukhopar [10]2 years ago

4 0

Answer:

The answer is 3.

Hope it helps..

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3 years ago

Help!! Answer !!! about to run out of time in test!!

Gemiola [76]

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

$\qquad \sf \dashrightarrow \: h {}^{2} = {8}^{2} + {6}^{2}$

$\qquad \sf \dashrightarrow \: h {}^{2} = {36}^{} + {64}^{}$

$\qquad \sf \dashrightarrow \: h {}^{2} = 100$

$\qquad \sf \dashrightarrow \: h {}^{} = \sqrt{100}$

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Now, let's find the asked values ~

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{opposite \: side}{hypotenuse}$

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{6}{10}$

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{3}{5} \: or \: 0.6 \: units$

For Cos y :

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{adjcant \: side}{hypotenuse}$

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{6}{10}$

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As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

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Hope it helps ~

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3 years ago

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kodGreya [7K]

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3 years ago

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3 years ago

Read 2 more answers

Mario is constructing a wall around a rectangular area which will cover a maximum of 60 square feet. The length of the wall will

Feliz [49]

Answer:

$W \le 6$

Step-by-step explanation:

Given

$Area = 60ft^2\ (max)$

$Length = 10ft$

Required

Represent the width as an inequality

First, we represent the area as an inequality.

$Area = 60ft^2\ (max)$

max as used above means less than or equal to.

So, we have:

$Area \le 60$

The area of a rectangle is:

$Area = L * W$

So, we have:

$L * W \le 60$

Substitute 10 for L

$10 * W \le 60$

Divide both sides by 10

$\frac{10 * W}{10} \le \frac{60}{10}$

$W \le \frac{60}{10}$

$W \le 6$

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3 years ago