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alexdok [17]
3 years ago
9

What is the number of moles in 432 g Ba(NO3)2? A. 0.237 mol B. 0.605 mol C. 1.65 mol D. 3.66 mol

Chemistry
1 answer:
Montano1993 [528]3 years ago
6 0

Answer:

C

Explanation:

Since Moles=mass/molar mass

Mass=432g

Molar mass=261g/mol

Moles=1.65mol

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Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

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\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}

To calculate the depression in freezing point, we use the equation:

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\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

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Putting values in above equation, we get:

0-\text{Freezing point of solution}=2\times 1.86^oC/m\times \frac{5\times 1000}{74.55g/mol\times 550}\\\\\text{Freezing point of solution}=-0.454^oC

Hence, the freezing point of solution is -0.454°C

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