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Anna [14]
3 years ago
11

A mixture of He, Ne, and N2 gases has a pressure of 0,898 atm. If the pressures of He and Ne are 0.336 atm and 0.106 atm, respec

tively, what is the partial pressure of N2 in the mixture?
Chemistry
1 answer:
Alchen [17]3 years ago
5 0

Answer:

Pressure for N₂ = 0.456 atm

Explanation:

There is law for gases which states that the sum of partial pressures of each gas in a mixture, is equal to the total pressure of the system.

For this case, we have a mixture of He, Ne and N₂

Then Total pressure is 0.898 atm

He's pressure + Ne's pressure + N₂'s pressure = 0.898 atm

N₂'s pressure = 0.898 atm - 0.336 atm - 0.106 atm

Pressure for N₂ = 0.456 atm

This is called the Dalton's law of partial pressures.

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Ilia_Sergeevich [38]

Answer:

The majority of chemical processes are reactions that occur in solution. Important industrial processes often utilize solution chemistry. "Life" is the sum of a series of complex processes occurring in solution. Air, tap water, tincture of iodine, beverages, and household ammonia are common examples of solutions.

four types of solution:

Turpentine as a solvent are used in the production of paints, inks and dyes. ↔Water as a solvent is used in the making of food, textiles, soaps and detergents. ↔Alloys are solid solutions that are used in the manufacture of cars, aerospace and other vehicles.

Explanation:

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5 0
3 years ago
A 3.8-mol sample of KClO3 was decomposed according to the equation. How many moles of O2 are formed assuming 100% yield?
kari74 [83]

Answer:

5.7 moles of O2

Explanation:

We'll begin by writing the balanced decomposition equation for the reaction. This is illustrated below:

2KClO3 —> 2KCl + 3O2

From the balanced equation above,

2 moles of KClO3 decomposed to produce 3 moles of O2.

Next, we shall determine the number of mole of O2 produced by the reaction of 3.8 moles of KClO3.

Since 100% yield of O2 is obtained, it means that both the actual yield and theoretical yield of O2 are the same. Thus, we can obtain the number of mole of O2 produced as follow:

From the balanced equation above,

2 moles of KClO3 decomposed to produce 3 moles of O2.

Therefore, 3.8 moles of KClO3 will decompose to produce = (3.8 × 3)/2 = 5.7 moles of O2.

Thus, 5.7 moles of O2 were obtained from the reaction.

3 0
3 years ago
Please helppp !!
Alex787 [66]
D ................................
7 0
3 years ago
How many answered does this question have , and which ?
Leviafan [203]
X rays and Gamma Rays.
4 0
3 years ago
Can the excess reactant control the percentage yield
katrin2010 [14]

Explanation:

when one reactants is in excess, there will always be some left over. The other reactants becomes limiting factor and controls show much of each product is produced.while using excess percentage yields this is at the expense of atom economy.

6 0
3 years ago
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