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Anna [14]
3 years ago
11

A mixture of He, Ne, and N2 gases has a pressure of 0,898 atm. If the pressures of He and Ne are 0.336 atm and 0.106 atm, respec

tively, what is the partial pressure of N2 in the mixture?
Chemistry
1 answer:
Alchen [17]3 years ago
5 0

Answer:

Pressure for N₂ = 0.456 atm

Explanation:

There is law for gases which states that the sum of partial pressures of each gas in a mixture, is equal to the total pressure of the system.

For this case, we have a mixture of He, Ne and N₂

Then Total pressure is 0.898 atm

He's pressure + Ne's pressure + N₂'s pressure = 0.898 atm

N₂'s pressure = 0.898 atm - 0.336 atm - 0.106 atm

Pressure for N₂ = 0.456 atm

This is called the Dalton's law of partial pressures.

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Describe the relationship between"q" and energy in the melting of an ice cube.
klio [65]

Answer:

Now "q" is  the heat and energy is the capacity of any object or body ton perform any work. So we can relate them if we take the term specific heat in consideration.

As specific heat is the the amount of heat required to raise the temperature of an object in specific from one degree Celsius, for ice it is 2.108 kJ/kgK.

Explanation:

  • c = specific heat capacity,

  • q = heat

  • ΔT = change in temperature

So, we have:

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3 years ago
The VSEPR model was developed before any xenon compounds had been prepared. Thus, these compounds provided an excellent test of
Natalka [10]

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<h3>What is mole ratio?</h3>

The mole ratio is the ratio of any two compounds' mole amounts that are present in a balanced chemical reaction.

A comparison of the ratios of the molecules required to accomplish the reaction is given by the balancing chemical equation.

A mole ratio is a conversion factor used in chemical reactions to link the mole quantities of any two compounds. A conversion factor's numbers are derived from the balanced chemical equation's coefficients.

To learn more about mole ratio from the given link:

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6 0
2 years ago
How much heat is lost when 0.440 mol of steam condenses at 100 °C?
dusya [7]

Answer:

17,890 J

Explanation:

The amount of heat released by a gaseous substance when it condenses is given by the formula

Q=n\lambda_v

where

n is the number of moles of the substance

\lambda_v is the latent heat of vaporization

The formula can be applied if the substance is at its vaporization temperature.

In this problem, we have:

n = 0.440 mol is the number of moles of steam

\lambda_v=40,660 J/mol is the latent heat of vaporization of water

And the steam is already at 100C, so we can apply the formula:

Q=(0.440)(40660)=17,890 J

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Reference image attached

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Please see the attached image.

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