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marin [14]
3 years ago
7

2. Al(OH),(s) + 3 HCl(aq) à 3 H2O(l) + AlCl3(aq). This reaction shows how aluminum hydroxide

Chemistry
1 answer:
sveta [45]3 years ago
7 0

This tablet <u>insufficient</u> to neutralize the acid in the patient's stomach

<h3>Further explanation</h3>

Reaction

Al(OH)₃(s) + 3HCl(aq) ⇒ 3 H₂O(l) + AlCl₃(aq)

0.25 g of  Aluminum hydroxide-Al(OH)₃ , mol (MW=78 g/mol) :

\tt \dfrac{0.25}{78}=0.00321

mol HCl : mol Al(OH)₃ = 3 : 1

\tt mol~HCl=3\times 0.00321=0.00963

mass HCl (MW=36,46 g/mol) :

\tt 0.00963\times 36.46=0.351

0.351 < 0.88⇒this tablet insufficient to neutralize the acid

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