Answer:
1) ΔACD is a right triangle at C
=> sin 32° = AC/15
⇔ AC = sin 32°.15 ≈ 7.9 (cm)
2) ΔABC is a right triangle at C, using Pythagoras theorem, we have:
AB² = AC² + BC²
⇔ AB² = 7.9² + 9.7² = 156.5
⇒ AB = 12.5 (cm)
3) ΔABC is a right triangle at C
=> sin ∠BAC = BC/AB
⇔ sin ∠BAC = 9.7/12.5 = 0.776
⇒ ∠BAC ≈ 50.9°
4) ΔACD is a right triangle at C
=> cos 32° = CD/15
⇔ CD = cos32°.15
⇒ CD ≈ 12.72 (cm)
Step-by-step explanation:
Answer:
how are we supposed to know that
The length of BC is 72 I hope this will help uh
Answer:
Therefore Lateral Area of Cone is 189.97 yd².
Step-by-step explanation:
Given:
Slant height = 12.1 yd
Diameter = 10 yd
∴ Radius = half of Diameter = 10 ÷ 2 = 5 yd
To Find:
Lateral Area of Cone = ?
Solution:
We know that,

Substituting the given values we get

Therefore Lateral Area of Cone is 189.97 yd².