let t = time (hrs) that they are 50 mi apart
Use pythag here; a^2 + b^2 = c^2; dist = speed * time
(30t)^2 (40t)^2 = 50^2
900t^2 + 1600t^2 = 2500
It's obvious that t = 1 hr
Answer:
The smaller number is 0.6666... repeating, and the larger number is 1.3333... repeating.
Step-by-step explanation:
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