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sertanlavr [38]
3 years ago
12

May someone help me on this question please

Mathematics
1 answer:
vladimir1956 [14]3 years ago
8 0
The insurance company will make an average of $34.00 on each student in the policy

3000 • 40 = 120000

120000 - 18000 = 102000

102000 / 3000 = 34

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(2,40) is the ordered pair where the 2 lines meet
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\large \bigstar \frak{ } \large\underline{\sf{Solution-}}

Consider, LHS

\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

We know,

\begin{gathered}\boxed{\sf{  \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered}  \\  \\  \text{So, using this identity, we get} \\  \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

We know,

\begin{gathered}\boxed{\sf{  \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered}  \\

So, using this identity, we get

\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

can be rewritten as

\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}

<h2>Hence,</h2>

\begin{gathered} \\ \rm\implies \:\boxed{\sf{  \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}

\rule{190pt}{2pt}

5 0
2 years ago
Can anyone help me with 15a b c
Pie

a. The independent variable is r. The dependent variable is m.

b. The domain is the set of numbers used in the independent variable. You can rent 0 videos, or 1 video, or 2 videos, etc., up to the amount of money you have. If you rent 0 videos, you are left with m = 30 - 3r = 30 - 3(0) = 30 - 0 = 30 dollars. If you rent 10 videos, you will have m = 30 - 3(10) = 30 - 30 = 0 dollars left. The domain is {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. The range is {0, 3, 6, 9, 12, 15, 18, 21, 24, 27, 30}. Both the domain and range are discrete.

c. I can't do it online.

7 0
3 years ago
Can help me find area and perimeter step by step
Vera_Pavlovna [14]

Answer:

  • area: 16.28 ft²
  • perimeter: 17.05 ft

Step-by-step explanation:

The figure is shown as being composed of a semicircle and a triangle. You know the formula for the area of a circle is ...

  A = πr²

The radius of the semicircle is half its diameter, so is (4 ft)/2 = 2 ft. Then the area of a circle with radius 2 feet is ...

  A = π(2 ft)² = 4π ft²

Our semicircle has half that area, so ...

  area of semicircle = (4π ft²)/2 = 2π ft² ≈ 6.283 ft²

__

The area of the triangle is given by the formula ...

  A = (1/2)bh

Here, the base is shown as 4 ft, and the height is shown as 5 ft. Then the triangle area is ...

  triangle area = (1/2)(4 ft)(5 ft) = 10 ft²

So, the total area of the composite figure is ...

  figure area = area of semicircle + triangle area

  = 6.283 ft² + 10 ft² ≈ 16.283 ft² . . . . area of the figure

__

The perimeter of the curved portion of the semicircle is half the circumference of a circle of radius 2 ft. It will be ...

  curved perimeter = (1/2)(2πr) = πr = π(2 ft) = 2π ft ≈ 6.283 ft

The length of each side of the triangle can be found from the Pythagorean theorem. Each side of the triangle is the hypotenuse of a right triangle with legs 2 ft and 5 ft. Then it will be ...

   triangle side length = √(2² +5²) ft = √29 ft ≈ 5.385 ft

The total perimeter is ...

   perimeter = 2 × triangle side length + semicircle length

  = 2×(5.385 ft) + 6.283 ft = 17.054 ft

The perimeter of the figure is about 17.05 feet.

4 0
3 years ago
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