Can someone please help me I really need to pass this question!!!!
1 answer:
Answer:
a ≈ 5.3
Step-by-step explanation:
Using Pythagoras' theorem
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
a² + 6² = 8², that is
a² + 36 = 64 ( subtract 36 from both sides )
a² = 28 ( take the square root of both sides )
a = ≈ 5.3 ( to the nearest tenth )
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Answer:
32,292,000
Step-by-step explanation:
In your question, it asks how many license plate combinations we could make WITHOUT repeats.
We need some prior knowledge to answer this question.
We know that:
- There are 26 letters in the alphabet
- We can make 10 digits (0 - 9)
With the information we know above, we can solve the question.
Since we CAN'T have repeats, we would be excluding a letter or number for each license plate.
We're going to need to multiply each "section" in order to find how many combinations of license plates we can make.
We decrease by one letter and one number in each section since we can't have repeats.
Now, we can solve.
Work:
When you're done multiplying, you should get 32,292,000.
This means that there could be 32,292,000 different combinations of license plates.
<h3>I hope this helps you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>