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The minimum value for g(x)=x² - 10x + 16 is -9
<h3>How to determine the minimum value?</h3>
The function is given as:
g(x)=x² - 10x + 16
Differentiate the function
g'(x) = 2x - 10
Set the function 0
2x - 10 = 0
Add 10 to both sides
2x = 10
Divide by 2
x = 5
Substitute 5 for x in g(x)
g(5)=5² - 10*5 + 16
Evaluate
g(5) = -9
Hence, the minimum value for g(x)=x² - 10x + 16 is -9
Read more about quadratic functions at:
brainly.com/question/7784687
The gcf of both 6 and 48 is 6. So, in simplest form, the ration would be: 1:6 or 1 hour:6 minutes :)
Answer: x=−3 or x=13
Step-by-step explanation:
Step 1: Subtract 39 from both sides.
x2−10x−39=39−39
x2−10x−39=0
Step 2: Factor left side of equation.
(x+3)(x−13)=0
Step 3: Set factors equal to 0.
x+3=0 or x−13=0
x=−3 or x=13