Answer: 11
Step-by-step explanation:
1. 17-1 = 16
2. 16-5= 11
In this question, it is given that
A new youth activity center is being built in oak valley. the perimeter of the rectangular playing field is 332 yards. the length of the field is 5 yards less than double the width.
Let the width is x yards . And length is 5 yards less than double the width, so length is (2x-5) yards .
Perimeter is the sum of all sides, that is
So the width is 57 yards and length is
Answer:
√5.
Step-by-step explanation:
Tan A = 1/2 means that the right triangle containing angle A has legs of length 1 and 2 units. So the hypotenuse = √(1^2 + 2^2) = √5 (using the Pythagoras theorem). The side opposite to < A = 1 unit and the adjacent side = 2 (as tan = opposite / adjacent).
so cos A = adjacent / hypotenuse = 2/√5.
and sin A = opposite / hypotenuse = 1 / √5
cos A / sin A = 2/√5 / 1/ √5 = 2.
sin A / (1 + cos A) = 1/√5 (1 + 2/ √5)
= 1 / √5 ( (√5 + 2) /√5)
= 1 / (√5 + 2)
So the answer is:
2 + 1 /(√5 + 2).
We can simplify it further by multiplying top and bottom of the fraction by the complement of √5 + 2 which is √5 - 2.
2 + 1 / (√5 + 2)
= 2(√5 + 2) + 1 / (√5 + 2 )
= { 2(√5 + 2) + 1 } / (√5 + 2)
Multiplying this by √5 - 2 / √5 - 2 we get:
(2(5 - 4) + √5 - 2) / (5 -4)
= 2 + √5 - 2 / 1
= √5.
Answer:
Statistical inference is the process of using data analysis to deduce properties of an underlying probability distribution. Inferential statistical analysis infers properties of a population, for example by testing hypotheses and deriving estimates.
Answer:
- $17,500 at 8%
- $17,500 at 14%
Step-by-step explanation:
The fraction that needs to be invested at the higher rate is ...
(11% - 8%)/(14% -8%) = 3%/6% = 1/2
Half the money should be invested at each of the rates:
$17,500 for 8% return
$17,500 for 14% return.
_____
If you let x represent the amount at the higher rate, then the total return is ...
14%x + 8%(35000 -x) = 11%(35000)
(14% -8%)x = (11% -8%)(35000) . . . . subtract 8%·35000
x = (11% -8%)/(14% -8%)×35000 . . . . divide by the coefficient of x
Note that this formula is exactly the one we started with, above.
