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Novay_Z [31]
3 years ago
7

If a= 5, b= 8, and c= ½ 6a - 2b + bc

Mathematics
1 answer:
Rainbow [258]3 years ago
8 0

Answer:

18

Step-by-step explanation:

6x5=30

2x8=16

8x1/2=4

30-16=14

14+4=18

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It would be $2000 for that month.
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What is 2.20 rounded to the nearest tenth?
Musya8 [376]
2.20 rounded to the nearest tenth is 2.2 it is already rounded if it was 2.29 it would be 2.3 
7 0
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The function ƒ(x) = x is vertically translated 1 unit up and then reflected across the y-axis. What's the new function g(x)?
tigry1 [53]

Answer:

C

Step-by-step explanation:

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4 0
2 years ago
What is the surface area of this triangular prism rounded to the nearest tenth? A) 48.6km2 B) 63.4 km2 C) 72.6 km2 D) 84.4 km2
Mekhanik [1.2K]

Correct option B)63.4km^2 .

<u>Step-by-step explanation:</u>

We have the following figure attached as shown below.

Now, this triangular prism have 2 similar right angled surfaces and 3 rectangular surfaces , Let's calculate area for all of them:

2 similar right angled surfaces

We know that area of triangle = \frac{1}{2} b(h)

⇒ area = \frac{1}{2} b(h)

⇒ area = \frac{1}{2} (3.6)(7.7)

⇒ area = 13.86km^{2}

But there 2 such surfaces so , area = 2(13.86) = 27.72km^2

3 rectangular surfaces

Area of rectangle = length(breadth)

⇒ area_1 = 3.6(1.8)

⇒ area_1 = 6.48km^2

⇒ area_2= 7.7(1.8)

⇒ area_2 = 13.86km^2

⇒ area_3 = 8.5(1.8)

⇒ area_2 = 15.3km^2

Total area =6.48 + 13.86 + 15.3 = 35.64km^2

Adding area of 2 similar right angled surfaces & 3 rectangular surfaces:

Area = 27.72+35.64 = 63.36km^2 = 63.4km^2

Correct option B)63.4km^2 .

4 0
2 years ago
Read 2 more answers
Now, he wants to wrap it with wrapping paper. If the length of the shoebox measures 10 in, the width measures 5 in, and the heig
julia-pushkina [17]

The amount of wrapping paper he need to cover the shoebox is 190 square inches

<h3>Surface area of a box</h3>

The formula for calculating the surface area of a box is expressed as:

SA = 2(lw + wh + lh)

where

l is the length

w is the width

h is the height

Given the following parameters

l = 10in

w = 5in

h =3in

Substitute

S = 2(10*5 + 5*3 + 10*3)

S = 2(50+15+30)

S = 2(95)

S = 190 square inches

Hence the amount of wrapping paper he need to cover the shoebox is 190 square inches

Learn more on surface area of box here: brainly.com/question/26161002

#SPJ1

6 0
1 year ago
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