All categories

3 years ago

What is a necessary step for constructing perpendicular lines through a point on a line?

Mathematics

1 answer:

mina [271]3 years ago

8 0

Draw arcs on either side of a given point on the line

You might be interested in

You spend $4.50 on 5 pounds of apples. What is the unit rate in dollars per pound?

vredina [299]

Answer:

$0.90 per pound.

Step-by-step explanation:

4.50:5

5/5=1

4.50/5=0.90

5 0

2 years ago

Read 2 more answers

$46 shoes; 2.9% tax what is the answer?

Dominik [7]

59.34 ---------------

4 0

2 years ago

Read 2 more answers

For number 6, evaluate the definite integral.

maks197457 [2]

$\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{(8+2x)^2}}\cdot dx\impliedby \textit{now, let's do some substitution}\\\\
-------------------------------\\\\
u=8+2x\implies \cfrac{du}{dx}=2\implies \cfrac{du}{2}=dx\\\\
-------------------------------\\\\$

$\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{u^2}}\cdot \cfrac{du}{2}\implies \cfrac{1}{2}\int\limits_{0}^{28}\ u^{-\frac{2}{3}}\cdot du\impliedby 
\begin{array}{llll}
\textit{now let's change the bounds}\\
\textit{by using } u(x)
\end{array}\\\\
-------------------------------\\\\
u(0)=8+2(0)\implies u(0)=8
\\\\\\
u(28)=8+2(28)\implies u(28)=64$

$\bf \\\\
-------------------------------\\\\
\displaystyle \cfrac{1}{2}\int\limits_{8}^{64}\ u^{-\frac{2}{3}}\cdot du\implies \cfrac{1}{2}\cdot \cfrac{u^{\frac{1}{3}}}{\frac{1}{3}}\implies \left. \cfrac{3\sqrt[3]{u}}{2} \right]_8^{64}
\\\\\\
\left[ \cfrac{3\sqrt[3]{(2^2)^3}}{2} \right]-\left[ \cfrac{3\sqrt[3]{2^3}}{2} \right]\implies \cfrac{12}{2}-\cfrac{6}{2}\implies 6-3\implies 3$

3 0

2 years ago

if you are asked to solve a system of equations in which there is no linear equation to start with, you can sometimes begin by i

DENIUS [597]

<u>Answer:</u>

The correct answer option is: True.

<u>Step-by-step explanation:</u>

Its true that if there is no linear equation to start with, you can isolate and substitute a variable that is squared in both the equation.

For example, for the given non linear equation, start by dividing both sides by coefficient of the variable.

Once you do that and isolate a variable, continue solving by substituting that variable into the other equation.

5 0

3 years ago

Is a rhombus always a square?

Nikolay [14]

Answer:

yes

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers