The minimum number of degrees that a regular hexagon can be rotated before it carries onto itself is 60 degrees (D).
Answer:
The function f(x) is not given, I used a different function but the approach and steps is the same .
Step-by-step explanation:
- Given the function f(x) = 2x2 - 8x + 5
compare with the normal quadratic equation ; ax2 + bx + c = f(x)
- since a is greater than zero i.e a > o {positive}
As such, it has a minimum
hence for minimum value; x = -b/2a
x = -(-8)/2 x 2
x = 8/4 = 2
plugging the values of x in f(x) ; f(2) = 2(2)^2 -8(2) + 5
f(2) = -3, hence it has minimum value and the minimum value is -3
Answer:
First multiply the first two terms so (-0.5)(-1.2) = 0.6 as product of two negative numbers is positive number.
Step-by-step explanation:
Im BIg BrAiN :D
Answer:
From 4-5 the shape is rotated 180 degrees.
Step-by-step explanation:
If you are standing up and you jump to face the other way your turning 180 degrees. If you turn to your side that would be 90 degrees and for a full turn 360 degrees.
Hope this helps, please leave any questions or concerns in the comments. Thanks
