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2 years ago

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(NEED ANSWER TODAY!) The dimensions of this figure are changed so that the new surface area is exactly 1/3 what it was originall

y.What is the new surface area?Enter your answer as a decimal in the box.

1 answer:

DochEvi [55]2 years ago

4 0

ANSWER: 202.46 if you need all the question answers just ask :D

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Suppose that insurance companies did a survey. They randomly surveyed 400 drivers and found that 320 claimed they always buckle

nirvana33 [79]

Answer:

i) $ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

And replacing we got:

$ME= 1.96*\sqrt{\frac{0.8 (1-0.8)}{400}} =0.0392$

ii) $Lower = 0.8-0.0392= 0.7608$

$Upper = 0.8 +0.0392= 0.8392$

Step-by-step explanation:

Notation and definitions

$X=320$ number of people that claimed always buckle up.

$n=400$ random sample taken

$\hat p=\frac{320}{400}=0.8$ estimated proportion of people that claimed always buckle up

$p$ true population proportion of people that claimed always buckle up

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

Part i

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

The margin of error is given by:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

And replacing we got:

$ME= 1.96*\sqrt{\frac{0.8 (1-0.8)}{400}} =0.0392$

Part ii

And the confidence interval would be given by:

$Lower = 0.8-0.0392= 0.7608$

$Upper = 0.8 +0.0392= 0.8392$

6 0

3 years ago

Help pls and thank :)

snow_tiger [21]

Answer:

-5

Step-by-step explanation:

slope is rise/run

so, the rise is -5, the 'run' is 1

so, -5

5 0

2 years ago

How many ways can 8 players be chosen from 10 players

maria [59]

There are 56 ways to choose the team

7 0

3 years ago

Mini made a recipe that yields 4 1/2 cups if each serving is 1/2 cup which expression will help many determine the number of ser

Black_prince [1.1K]

You have to divide the total about of cups by the serving size:

4 1/2 divided by 1/2 and you get the answer.

4 1/2 converted into an improper fraction is 9/2.

9/2 divided by 1/2 = 9

8 0

3 years ago

Read 2 more answers

Perimeter of rectangle is 48 inches area is 40 inches what are the length of the side

Aloiza [94]

$\bf \textit{perimeter of a rectangle}=p=side+side+side+side
\\\\
or\implies p=w+w+l+l\implies p=2w+2l
\\\\
p=2(w+l)\qquad 
\begin{cases}
w=width\\
l=length\\
------\\
p=48
\end{cases}\implies 40=2(w+l)\\\\
-----------------------------\\\\
\textit{area of it}=A=w\cdot l\qquad \begin{cases}
w=width\\
l=length\\
------\\
A=40
\end{cases}\implies 40=wl\\\\
-----------------------------\\\\$

$\bf thus\qquad 
\begin{cases}
40=2(w+l)\to \frac{40}{2}=w+l\to\frac{40}{2}-l=\boxed{w}
\\\\
40=wl\\
--------------\\
40=\left( \boxed{\frac{40}{2}-l} \right)\cdot l
\end{cases}$

solve for "l" to find its length

7 0

3 years ago