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2 years ago

12. How many cups are left in a half-gallon carton of orange juice after 3 cups are used?

Mathematics

1 answer:

tia_tia [17]2 years ago

8 0

The number of cups that are left in a half-gallon carton of orange juice after 3 cups are used is 5 cups.

To solve this question, we'll need to convert gallons to cups. This will be:

1 gallon = 16 cups. Therefore, 1/2 gallon will be = 1/2 × 16 = 8 cups.

In this case, we'll then subtract the number of cups that have been used from 8 cups. This will be:

= 8 cups - 3 cups .

= 5 cups.

Therefore, the number of cups that are left after 3 cups are used is 5 cups.

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3 years ago

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F(x)=x^5+(x+3)^2 which value completed the table

galben [10]

Answer:

three boys shared D 10,500.00 in the ratio 6:7:8.find the largest share.

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2 years ago

The scuba club has 20 members, 5 girls and 15 boys. What is the ratio of girls to boys in the scuba club?

Mariana [72]

5 girls : 15 boys

divide each by 5

1 girl: 3 boys

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2 years ago

The lee's spend $ 31 on movie tickets for 2 adults and 3 children. The Smith's spent $ 26 on movie tickets for 2 adults and 2 ch

Trava [24]

Answer:

Cost of adult ticket is $8 and Cost of children ticket is $5.

Step-by-step explanation:

Given:

Let the cost of each Adult ticket be 'x'.

Let the cost of each child ticket be 'y'.

Now Given:

The lee's spend $ 31 on movie tickets for 2 adults and 3 children.

Number of adult tickets = 2

Number of children ticket = 3

Total money spent = $31

So we can say that;

Total money spent is equal to sum Number of adult tickets multiplied by cost of each Adult ticket and sum Number of children tickets multiplied by cost of each child ticket.

framing in equation form we get;

$2x+3y=31 \ \ \ \ equation \ 1$

Also Given:

The Smith's spent $ 26 on movie tickets for 2 adults and 2 children

Number of adult tickets = 2

Number of children ticket = 2

Total money spent = $26

So we can say that;

Total money spent is equal to sum Number of adult tickets multiplied by cost of each Adult ticket and sum Number of children tickets multiplied by cost of each child ticket.

framing in equation form we get;

$2x+2y=26 \ \ \ \ equation \ 2$

Now Subtracting equation 2 from equation 1 we get;

$2x+3y-(2x+2y)=31-26\\\\2x+3y-2x-2y=5\\\\y=\$5$

Now substituting the value of y in equation 1 we get;

$2x+3y=31\\\\2x+3\times5 =31\\\\2x+15=31\\\\2x=31-15\\\\2x=16x\\\\\frac{2x}{2}\frac{16}{2}\\\\x=\$8$

Hence Cost of adult ticket is $8 and Cost of children ticket is $5.

6 0

2 years ago

Uan zhang bought a 10-year bond that pays 8. 25 percent semiannually for $911. 10. what is the yield to maturity on this bond? (

Radda [10]

The yield to maturity on this bond according to the trial-and-error approach is 9.66 percent.

According to the statement

we have given that the Uan zhang bought a 10-year bond that pays 8. 25 percent interest per 6 months.

And we have to find that the yield to maturity on this bond.

So, For this purpose,

The amount given is $911. 10.

Years to maturity = n = 10

Coupon rate = C = 8.25%

Semiannual coupon = $1,000 × (0.0825/2) = $41.25

Yield to maturity = i

Present value of bond = PB = $911.10

Use the trial-and-error approach to solve for YTM. Since the bond is selling at a discount, we know that the yield to maturity is higher than the coupon rate.

Try YTM = 9.4%:

= $522.90 + 391.54 ≅ $914.43

The YTM is approximately 9.66 percent. Using a financial calculator provided an exact YTM of 9.656 percent (2 × 4.828%).

So, The yield to maturity on this bond according to the trial-and-error approach is 9.66 percent.

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11 months ago