Answer:
= 6/1 × 17/2
= (6 × 17) / (1 × 2)
= 102/2
= 51/1
<span>= 51</span>
Not exactly sure but I think it's false hope this helps
The area of the trapezoid is x+11 cm.
Given a trapezoid has one side of (x+6) cm, the other side is 5 cm, and the height is 2 cm.
A two-dimensional quadrilateral consisting of the sum of non-adjacent parallel sides and a suitable non-parallel side is denoted as a trapezoid.
Now we will use the formula to find the area of a trapezoid
Area = 1/2 × (base 1 + base 2) × height
Here base 1 = (x+6) cm, base 2 = 5cm and height = 2cm
Substituting the values into the formula, we get
Area = 1/2 × (x+6+5) × 2
Area = 1/2 × (x+11) × 2
Area = x+11
Thus, the area of the given figure when one side is x+6, the other side is 5 cm and the height is 2 cm is x+11 cm.
Learn more about the area of trapezium from here brainly.com/question/15815316
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If it's to the thousands it's 6,000
<span>h(x)=<span>6<span>x−4</span></span></span> or <span>h(x)=6x−4</span>
<span>If the former, the domain is all real numbers, often denoted by the symbol </span>R<span>. </span>
<span>the range is </span><span>(0,∞)</span>
<span>asymptote is y = 0</span>
