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Ymorist [56]
3 years ago
7

Drag the tiles to the boxes to form correct pairs. Match the pairs of equivalent expressions.

Mathematics
2 answers:
Rashid [163]3 years ago
5 0

Answer:

The following pairs/results are matched:

  • 5\left(2t+1\right)+\left(-7t+28\right) = 3t+33
  • 3\left(3t-4\right)-\left(2t+10\right) = 7t-22
  • \left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right) = \frac{16t}{3}-\frac{23}{5}
  • \left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right) = -\frac{11}{4}t+36

Step-by-step explanation:

Lets solve all the expressions to match the results.

  • 5\left(2t+1\right)+\left(-7t+28\right)

<em>Solving the expression</em>

5\left(2t+1\right)+\left(-7t+28\right)

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

5\left(2t+1\right)-7t+28

10t+5-7t+28

3t+33

Therefore, 5\left(2t+1\right)+\left(-7t+28\right) = 3t+33

  • 3\left(3t-4\right)-\left(2t+10\right)

<em>Solving the expression</em>

3\left(3t-4\right)-\left(2t+10\right)

9t-12-\left(2t+10\right)

9t-12-2t-10

7t-22

Therefore, 3\left(3t-4\right)-\left(2t+10\right) = 7t-22

  • \left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right)

<em>Solving the expression</em>

\left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right)

\mathrm{Remove\:parentheses}:\quad \left(a\right)=a

4t-\frac{8}{5}-\left(3-\frac{4}{3}t\right)

4t-\frac{8}{5}-\left(-\frac{4t}{3}+3\right)

4t-\frac{8}{5}-3+\frac{4t}{3}

As

-3-\frac{8}{5}:\quad -\frac{23}{5}    and  \frac{4t}{3}+4t:\quad \frac{16t}{3}

So,

4t-\frac{8}{5}-3+\frac{4t}{3} will become \frac{16t}{3}-\frac{23}{5}

Therefore, \left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right) = \frac{16t}{3}-\frac{23}{5}

  • \left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right)

<em>Solving the expression</em>

\left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right)

\mathrm{Remove\:parentheses}:\quad \left(a\right)=a

-\frac{9}{2}t+3+\frac{7}{4}t+33

\mathrm{Group\:like\:terms}

\frac{9}{2}t+\frac{7}{4}t+3+33

\mathrm{Add\:similar\:elements:}\:-\frac{9}{2}t+\frac{7}{4}t=-\frac{11}{4}t

-\frac{11}{4}t+3+33

-\frac{11}{4}t+36

Therefore, \left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right) = -\frac{11}{4}t+36

Thus, the following pairs/results are matched:

  • 5\left(2t+1\right)+\left(-7t+28\right) = 3t+33
  • 3\left(3t-4\right)-\left(2t+10\right) = 7t-22
  • \left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right) = \frac{16t}{3}-\frac{23}{5}
  • \left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right) = -\frac{11}{4}t+36

Keywords: algebraic expression

Learn more about algebraic expression from brainly.com/question/11336599

#learnwithBrainly

mel-nik [20]3 years ago
3 0

Answer:

Step-by-step explanation:

5 (2t + 1) + (-7t + 28) = 3t + 33

(4t - 8/5) - (3 - 4/3t) = 16/3t - 23/5

3 (3t - 4) - (2t + 10) = 7t - 22

(-9/2x + 3) + (7/4x + 33) = -11/4x + 36

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23/40 is a rational number

Step-by-step explanation:

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3 years ago
Simplify each expression using the laws of exponents. No negative exponents should be in your final answer. (On the image attach
Cloud [144]

Answer:

<em>Answer</em><em> </em><em>is</em><em> </em><em>given below with explanations</em><em>. </em>

Step-by-step explanation:

by \: simplifying \: the \: given \: expression \: using \:  \\ law \: of \: exponents \: we \: get \\  \frac{15 {x}^{15}  {y}^{ - 3}  {z}^{4} }{18 {x}^{18}  { {y}^{4}  {z}^{ - 4} }^{} }  \\   = \frac{5  \: {x}^{ - 3}  {y}^{ - 7} {z}^{8}  }{6}  \\ we \: may \: also \: write \: as \\  =  \frac{5 {z}^{8} }{6 {x}^{3}  {y}^{7} }

formulae \: used  \ \: : \\  \frac{ {x}^{m} }{ { {x}^{n} }^{} }  =  {x}^{m - n}  \:  \:  \: and \\  {x}^{ - m}  =  \frac{1}{ {x}^{m} }

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

5 0
3 years ago
Read 2 more answers
Suppose y varies inversely with X, and y = 48 when x = 3. What is the value of x when y = 24?
olganol [36]

Answer:

C. 6

Step-by-step explanation:

Recall that inverse variation is given by:

\displaystyle y=\frac{k}{x}

Where <em>k</em> is the constant of variation.

We know that <em>y</em> = 48 when <em>x</em> = 3. Substitute:

\displaystyle (48)=\frac{k}{(3)}

Solve for <em>k: </em>

<em />k=3(48)=144<em />

<em />

Hence, our equation is:

\displaystyle y=\frac{144}{x}

We want to find <em>x</em> when <em>y</em> = 24. Substitute:

\displaystyle \frac{24}{1}=\frac{144}{x}

Cross-multiply:

24x=144

Divide both sides by 24. Hence:

x=6

Our answer is C.

3 0
3 years ago
132 days to 125.4 days percent of change
Evgen [1.6K]

Answer:

132 days to 125.4 days percent of change

Step-by-step explanation:

p= N-O/O x 100% where p is the percent change, is the New value and O is

the Old value. We are given the Old value (132) and the New value (125.4) which we can substitute into the formula to calculate the percent change:

p= 125.4-132/132 x 100%

p= -6.6/132 x 100%

p= (-660/132%)

p= -5%

5 0
11 months ago
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