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Sphinxa [80]
3 years ago
9

Find the product.

Mathematics
1 answer:
kozerog [31]3 years ago
8 0
-2b^2(3b^2-4b+9)
-6b^4+8b^3-18b^2
The answer is the second one down
Hope this helps!
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[3x^(2/3)] • [7x^(1/4)]<br><br> photo of equation above
aalyn [17]

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6 0
4 years ago
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What is the volume of the right rectangular prism below?<br> ​<br> ​
Allushta [10]

Answer:

Step-by-step explanation:

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3 0
3 years ago
Given h(x) = 5x + 2, solve for 2 when h(x) = -8.
san4es73 [151]

Answer:

\huge\boxed{\sf x = -2}

Step-by-step explanation:

\sf h(x) = 5x+2\\\\Put \ h(x) = -8\\\\-8 = 5x+2\\\\Subtract \ 2 \ to \ both \ sides\\\\-8-2 = 5x\\\\-10 = 5x\\\\Divide\ both \ sides \ by \ 5\\\\-10 / 5 = x \\\\x = -2 \\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
8 0
3 years ago
What is the expression equivalent to 64 - x^2
Murrr4er [49]

Answer: -(x+8)(x-8)

Step-by-step explanation:

-(x^2-64)

x^2-8^2x^2

x^2-8^2=(x+8)(x-8)

-(x+8)(x-8)

8 0
3 years ago
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What is x? I will give brainliest if you explain your answer.
horsena [70]

Answer:

  • x =  {0, π/2, 3π/2, 2π}

Step-by-step explanation:

  • cotx cos x - cot x = 0
  • cotx( cosx - 1) = 0

1. <u>cotx = 0</u>

  • x = π/2 + πn
  • In the interval [0, 2π] we have π/2 and 3π/2

2. <u>cosx = 1</u>

  • x  = 0 + 2πn
  • In the given interval we have 0 and 2π

<u>So the solution set is:</u>

  • x =  {0, π/2, 3π/2, 2π}

3 0
3 years ago
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