If a polynomial function f(x) has roots –8, 1, and 6i, what must also be a root of f(x)?

2 answers:

6 0

For any polynomial with a complex root, the imaginary part of the complex root always has positive and negaive component. Since one of the roots of this polynomial is 6i, then -6i must also be a root of the function.

ruslelena [56]3 years ago

4 0

Answer:

The answer is B : -6i

Step-by-step explanation:

You might be interested in

What was the first step when solving the equation below for x

exis [7]

B hope this helps you

8 0

3 years ago

Read 2 more answers

Plzzzzzzzz helppppp meeeeeeee

andriy [413]

The rectangle has an area of 18x8 = 144 sq in. The circle has an area of (pi)r^2 or (pi)3^2 =28.27sq in. Subtract 144 - 28.27 = 115.73

3 0

3 years ago

Math help :) Thank you!

Maru [420]

Answer:

1/2

Step-by-step explanation:

Total number of cards in a deck = 52

Total umber of red cards = 13 + 13 = 26

P(red card)

= 26/52

= 1/2

6 0

3 years ago

suppose that incomes of families in Newport Harbor are normally distributed with a mean of $750,000 and a standard deviation of

denis23 [38]

Answer: 0.345

Step-by-step explanation:

Given : The incomes of families in Newport Harbor are normally distributed with Mean : $\mu=\$ 750,000$ and Standard deviation : $\sigma= $250,000$