Answer:
Ix - 950°C I ≤ 250°C
Step-by-step explanation:
We are told that the temperature may vary from 700 degrees Celsius to 1200 degrees Celsius.
And that this temperature is x.
This means that the minimum value of x is 700°C while maximum of x is 1200 °C
Let's find the average of the two temperature limits given:
x_avg = (700 + 1200)/2 =
x_avg = 1900/2
x_avg = 950 °C
Now let's find the distance between the average and either maximum or minimum.
d_avg = (1200 - 700)/2
d_avg = 500/2
d_avg = 250°C.
Now absolute value equation will be in the form of;
Ix - x_avgI ≤ d_avg
Thus;
Ix - 950°C I ≤ 250°C
y + 8 = 1/3 (x+6)
With the given information, we can use the point-slope formula, , to write the equation of the line. Substitute values for the , , and in the formula to do so.
The represents the slope, so substitute in its place. The and represent the x and y values of one point the line intersects, so substitute -6 for and -8 for . This gives the following answer and equation (just make sure to convert the double negatives into positives:
(18.6 + 9.4) x 1/2^2= 7 hope it helps!