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Strike441 [17]
3 years ago
15

PLEASE HELP ME W THIS !! I RLLY SUCK AT MATH LOL

Mathematics
1 answer:
saw5 [17]3 years ago
5 0

Answer:

{5}^{3}  \times {5}^{ - 2}   \\  {5}^{3 - 2 }  \\  {5}^{1}

Step-by-step explanation:

if it doesn't work I'm sorry

You might be interested in
Evaluate the following integrals: 1. Z x 4 ln x dx 2. Z arcsin y dy 3. Z e −θ cos(3θ) dθ 4. Z 1 0 x 3 √ 4 + x 2 dx 5. Z π/8 0 co
Zigmanuir [339]

Answer:

The integrals was calculated.

Step-by-step explanation:

We calculate integrals, and we get:

1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}

2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}

3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}

4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}

5)  \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=

=\frac{3π+8}{64}

6)  ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x

7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}

8)  ∫ tan^5 (x) sec(x)  dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x

6 0
3 years ago
Can you please help me ​
shusha [124]

Answer:

1: inequality

2: solution

3: open circle

4: infinite

5: closed circle

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
2m divided by 3/9; m = 3/2
11Alexandr11 [23.1K]

Answer:

Not completely sure but I think 9

Step-by-step explanation:

In order to solve this equation, you would need to first multiply m by 2 to get 2 m. 3/2=1.5; 1.5*2 =3. 3/9 simplifies to 1/3

Then you would want to solve. So, you would need to divide 2 by 1/3 which would give you 9.

8 0
3 years ago
1. The US Mint has a specification that pennies have a mean weight of 2.5g. From a sample of 37 pennies, the mean weight is foun
Evgesh-ka [11]

Answer:

the pennies does not conform to the US mints specification

Step-by-step explanation:

z = (variate -mean)/ standard deviation

z= 2.5 - 2.4991 / 0.01648 = 0.0546

we are going to check the value of z in the normal distribution table, which is the table bounded by z.

checking for z= 0.0 under 55 gives 0.0219 (value gotten from the table of normal distribution)

we subtract the value of z from 0.5 (1- (0.5+0.0219)) = 0.4781 > 0.05claim

since 0.4781 > 0.05claim, therefore, the pennies does not conform to the US mints specification

the claim state a 5% significance level whereas the calculated significance level is 47.81%. therefore, the claim should be rejected

7 0
3 years ago
I just need help on #8.
andrey2020 [161]
What lesson is that?
4 0
3 years ago
Read 2 more answers
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