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3 years ago

PLEASE HELP ME W THIS !! I RLLY SUCK AT MATH LOL

Mathematics

1 answer:

saw5 [17]3 years ago

5 0

Answer:

${5}^{3} \times {5}^{ - 2} \\ {5}^{3 - 2 } \\ {5}^{1}$

Step-by-step explanation:

if it doesn't work I'm sorry

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Simplify 8(a+2)+2(2+3a)

Alexxx [7]

Expand

8a + 16 + 4 + 6a

Collect like terms

(8a + 6a) + (16 + 4)

Simplify

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3 years ago

7000 cm² is the same area as<br> .......... m².

Dennis_Churaev [7]

Answer:

1000cm²=0.1m²

so 7000cm²=0.7m²

Step-by-step explanation:

please mark me as brainliest

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3 years ago

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A baker uses 20 cups of flour to make 4 loves of bread. Use this to solve the question in the picture!

mariarad [96]

Answer:

60 cups of flour

Step-by-step explanation:

Since it takes 20 cups of flour for 4 loves of bread this means we're going to need to multiply 20x3=60

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3 years ago

Find the derivative of the function at P 0 in the direction of A. f(x,y,z) = 3 e^x cos(yz), P0 (0, 0, 0), A = - i + 2 j + 3k

Alik [6]

The derivative of $f(x,y,z)$ at a point $p_0=(x_0,y_0,z_0)$ in the direction of a vector $\vec a=a_x\,\vec\imath+a_y\,\vec\jmath+a_z\,\vec k$ is

$\nabla f(x_0,y_0,z_0)\cdot\dfrac{\vec a}{\|\vec a\|}$

We have

$f(x,y,z)=3e^x\cos(yz)\implies\nabla f(x,y,z)=3e^x\cos(yz)\,\vec\imath-3ze^x\sin(yz)\,\vec\jmath-3ye^x\sin(yz)\,\vec k$

and

$\vec a=-\vec\imath+2\,\vec\jmath+3\,\vec k\implies\|\vec a\|=\sqrt{(-1)^2+2^2+3^2}=\sqrt{14}$

Then the derivative at $p_0$ in the direction of $\vec a$ is

$3\,\vec\imath\cdot\dfrac{-\vec\imath+2\,\vec\jmath+3\,\vec k}{\sqrt{14}}=-\dfrac3{\sqrt{14}}$

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3 years ago

When doing currency exchange why is it better to carry the transaction out to five or six places rather than round to cents. Wha

k0ka [10]

When rounding earlier, it could be screwing you out of an extra few cents that you might eventually need for tax

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3 years ago

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