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tia_tia [17]
3 years ago
7

23.450÷345

345" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
wariber [46]3 years ago
3 0

Answer:

0.0679710145

I hope this will help you

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what is the image of the point ( -4, 8) after a rotation of 90° counterclockwise about the origin ​
lesya [120]

Answer:(-8,-4)

Step-by-step explanation:

5 0
3 years ago
A phone company offers two monthly plans. Plan A costs $ 20 plus an additional $0.12 for each minute of calls. Plan B costs $13
Shalnov [3]

Let:

• y, be the cost of the plan

,

• x, be the minutes spend on call

This way, we'll have:

Plan A:

y=0.12x+20

Plan B:

y=0.17x+13

If the two plans cost the same, we'll have that:

0.12x+20=0.17x+13

Solving for x :

\begin{gathered} 20-13=0.17x-0.12x \\ \rightarrow7=0.05x \\ \rightarrow\frac{7}{0.05}=x \\  \\ \Rightarrow x=140 \end{gathered}

A) The two plans will cost the same for 140 minutes on call

The cost will be:

\begin{gathered} y=0.12(140)+20 \\ \Rightarrow y=36.8 \end{gathered}

B) $36.80

3 0
2 years ago
Solve − 2 x − 10 y = 10
skad [1K]

Answer:

x=-10 and y=1

Step-by-step explanation:

-2(-10)=20

-10(1)=-10

20-10=10

8 0
3 years ago
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Hey I'm Chloe can you help me, thanks, I'll give you Brainiest :)
defon

Answer:

4 is the answer

Step-by-step explanation:

gjgffgbfy

3 0
4 years ago
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Find the sum of the geometric series 512+256+...+4<br> a) 510<br> b) 1,022<br> c) 1,020<br> d) 1,016
zzz [600]

Answer:

Option C. 1020

Step-by-step explanation:

From the question given above,

512 + 256 +... + 4 =?

We'll begin by calculating the number of terms in the sequence. This can be obtained as follow:

First term (a) = 512

Common ratio (r) = 2nd term / 1st term

Common ratio (r) = 256 /512

Common ratio (r) = 1/2

Last term (L) = 4

Number of term (n) =?

Tₙ = arⁿ¯¹

L = arⁿ¯¹

4 = 512 × (1/2)ⁿ¯¹

Divide both side by 512

4 / 512 = (1/2)ⁿ¯¹

1/128 = (1/2)ⁿ¯¹

Express 128 in index form with 2 as the base

1/2⁷ = (1/2)ⁿ¯¹

(1/2)⁷ = (1/2)ⁿ¯¹

Cancel 1/2 from both side

7 = n – 1

Collect like terms

7 + 1 = n

n = 8

Thus, the number of terms is 8

Finally, we shall determine the sum of the series as follow:

First term (a) = 512

Common ratio (r) = 1/2

Number of term (n) = 8

Sum of 8th term (S₈) = ?

Sₙ = a[1 – rⁿ] / 1 – r

S₈ = 512 [1 – (½)⁸] / 1 – ½

S₈ = 512 [1 – 1/256] ÷ ½

S₈ = 512 [255/256] × 2

S₈ = 2 × 255 × 2

S₈ = 1020

Thus, the sum of the series is 1020.

5 0
3 years ago
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