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3 years ago

55 is the sq root of what

Mathematics

2 answers:

Cerrena [4.2K]3 years ago

4 0

Answer:

3025

Step-by-step explanation:

andriy [413]3 years ago

3 0

Answer:

7.4162

Step-by-step explanation:

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The sum of two numbers is 17. Their difference is 3. Find the numbers.

Afina-wow [57]

Answer: 7 & 10

Step-by-step explanation:

7+10=17

10-7=3

8 0

3 years ago

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Which of these expressions CANNOT be simplified by combining like terms?

densk [106]

$5ab^{3} +7-3a^{2} b ^{2} +a^{3}b+10$ can be simplified to by adding the 7 and 10 to get $a^{3}b-3a^{2} b ^{2}+ 5ab^{3} + 17$ .

$5ab^{3}+3a^{2}b^{2}+a^{3}b -10$ cannot be simplified any more by combining like terms.

By distributing the 2b into the parentheses, you can simplify the expression:
$5ab^{3}+2b(3ab^{2})+a^{3}b-10\\
5ab^{3}+6ab^{3}+a^{3}b-10\\
11ab^{3}+a^{3}b-10$

Here you can just add:
$5a^{3}b^{3}+3a^{2}b^{2}+a^{3}b^{3}-10ab\\
6a^{3}b^{3}+3a^{2}b^{2}-10ab$

Thus, the only expression that cannot simplify any more using adding like terms is the second, $5ab^{3}+3a^{2}b^{2}+a^{3}b -10$ .

3 0

3 years ago

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The play started at 2:10 p.m and ended at 3:22 p.m How long did the play last?

hodyreva [135]

1 hour and 12 minutes

8 0

3 years ago

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70. Suppose that you currently have one credit card with a balance of $10,000 at an annual rate of 24.00% interest. You have sto

Simora [160]

Answer:

$1+r+r^{2}+r^{3}+.....+r^{n-1} = \frac{1-r^{n}}{1-r}$

Step-by-step explanation:

Taking the succession:

$1+r+r^{2}+r^{3}+.....+r^{n-1}$

You can multiply and divide by 1-r without chaging the result:

$\frac{1-r}{1-r} (1+r+r^{2}+r^{3}+.....+r^{n-1})$

Distributing the upper part of the fraction you have:

$\frac{1}{1-r} (1-r+r-r^{2}+r^{2}-r^{3}+r^{3}-r^{4}+.....+r^{n-1}-r^{n})$

As can be seen all the intermediate members will be canceled by a same member with opposite sign, only $(1-r^{n})$ will be left so:

$1+r+r^{2}+r^{3}+.....+r^{n-1} = \frac{1-r^{n}}{1-r}$

5 0

3 years ago

PLEASE HELPPP!!!!!!!!!!!!!

Leto [7]

For this case we have:

Question 1:

According to Heron's formula, the area of a triangle is given by:

$A=\sqrt{(s(s-a)(s-b)(s-c))}$

Where a, b and c are the sides of the triangle and s is the semi-perimeter of the triangle given by:

$s=\frac{(a+b+c)}{2}$

Let:

$a = 20mm\\b = 23mm\\c = 27mm$

We have s:

$s=\frac{(20+23+27)}{2}\\s=\frac{70}{2}\\s=35$

Substituting in the formula of the area:

$A=\sqrt{(35(35-20)(35-23)(35-27))}\\A=\sqrt{(35(15)(12)(8))}\\A=\sqrt{(50400)}\\A=224.5mm^2$

Thus, the area of the triangle is $A = 224.5mm ^ 2$

Answer:

$A = 224.5mm ^ 2$

Question 2:

The area of a traingule can be expressed as:

$A=\frac{(b*h)}{2}$

Where:

b: Base of the triangle

h: Triangle height

Let:

$b = 20m\\h = 18m$

Substituting the values in the expression we have:

$A=\frac{(20*18)}{2}\\A=\frac{360}{2}\\A=180m^2$

Thus, the area of the triangle is $A = 180m ^ 2$

Answer:

$A = 180m ^ 2$

Question 3:

It is known that the area of a rectangle is given by:

$A = l * w$

Where:

l: It is the length of the rectangle

w: It is the width of the rectangle

So:

$l = 9 feet\\w = 8 feet$

Substituting:

$A = (9 * 8) feet ^ 2\\A = 72 feet ^ 2$

Thus, the area of Laura's carpet is given by $A = 72 feet ^ 2$

Answer:

$A = 72 feet ^ 2$

Question 4:

We must take out the area of the outer wall, given by a rectangle, then:

$A = l * a$

Where:

l: It is the length of the rectangle

a: It is the height of the rectangle

We have:

$l = 48 feet\\a = 9 feet$

Substituting in the formula we have:

$A = (48 * 9) feet ^ 2\\A = 432ft ^ 2$

Thus, the area of the exterior wall is given by: $A = 432 feet ^ 2$

$432ft ^ 2> 400ft ^ 2$

So, a can of paint is not enough to cover the exterior wall.

Answer:

A can of paint is not enough to cover the exterior wall.

Question 5:

A regular hexagon is formed by 6 equal triangles. The area of the hexagon is given by:

$A=\frac{(perimeter* apothem)}{2}$

Where the perimeter is given by the sum of the sides, that is:

$perimeter = (10 + 10 + 10 + 10 + 10 + 10) cm\\perimeter = 60cm$

And the apothem is the height of each of the triangles that make up the hexagon, that is:

$apothem = 5cm$

Substituting in the formula:

$A=\frac{(60*5)}{2}\\A=\frac{300}{2}\\A=150cm^2$

Thus, the area of the hexagon is $A = 150cm ^ 2$

Answer:

$A = 150cm ^ 2$

7 0

3 years ago