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julsineya [31]
3 years ago
10

What is the sum of ​ 13 5/7 + 13/28 ​ ?

Mathematics
1 answer:
nydimaria [60]3 years ago
4 0

<em><u>Look at the attached picture⤴</u></em>

<em><u>Hope it will help u....:)</u></em>

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O is the centroid. Find the value of x. (Sorry if u cant see the photo :/, but this is Geometry btw)
klemol [59]

Answer: x = 6

==============================================

Explanation:

The medians of a triangle meet up at the centroid in such a way that they cut each other at a ratio of 2:1, meaning that one part of the median is twice as long as the other. In this case, MO is two times longer than OP, so,

OP = 2*MO

and

MP = MO + OP

MP = MO + 2*MO .... replace OP with 2*MO

MP = 3*MO

9x-24 = 3*(x+4) ... plug in the given expressions

9x-24 = 3x+12

9x-3x = 12+24

6x = 36

x = 36/6

x = 6

8 0
3 years ago
A large box contains 18 small boxes and each small box contains 25 chocolate bars. How many chocolate bars are in the large box?
Katarina [22]
You need to multiply 25 by 18 to find the total.

25 x 18 = 450.

There are 450 chocolate bars in the large box
5 0
3 years ago
Read 2 more answers
Please explain your method and how you solved. Thanks.
Hoochie [10]
Count the amount of 1 bag then you know one bag. The same amount has to be in each bag. So just multiply it by 3. The answer per bag is 10 so there are 30 blocks
7 0
3 years ago
prove that the quadrilateral whose vertices are the points A(-1,1), B(-3,4), C(1,5) and D(3,2) is a parallelogram.
Vsevolod [243]

Answer:

Since \overrightarrow{AB} = \overrightarrow{DC} and \overrightarrow{AD} = \overrightarrow{BC}, then the quadrilateral ABCD is a parallelogram.

Step-by-step explanation:

First, we label each point of the quadrilateral with the help of a graphing tool. If the quadrilateral ABCD is a parallelogram, then \overrightarrow{AB} = \overrightarrow{DC} and \overrightarrow{AD} = \overrightarrow{BC}. If we know that A(x,y) =(-1, 1), B(x,y) =(-3,4), C(x,y) = (1,5) and D(x,y) = (3,2), then the measure of each vector is, respectively:

\overrightarrow{AB} = (-3,4)-(-1,1)

\overrightarrow{AB} = (-2, 3)

\overrightarrow{DC} = (1,5)-(3,2)

\overrightarrow{DC} = ( -2,3)

\overrightarrow{AD} = (3,2)-(-1,1)

\overrightarrow{AD} = (4, 1)

\overrightarrow{BC} = (1,5)-(-3,4)

\overrightarrow{BC} = (4, 1)

Since \overrightarrow{AB} = \overrightarrow{DC} and \overrightarrow{AD} = \overrightarrow{BC}, then the quadrilateral ABCD is a parallelogram.

7 0
3 years ago
Can someone help me with this
o-na [289]

Answer:

the third option is the correct

3 0
2 years ago
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