7.
(2b^2+7b^2+b)+(2b^2-4b-12)
(9b^2+b)+(2b^2-4b-12)
9b^2+b+2b^2-4b-12
11b^2+b-4b-12
11b^2-3b-12
8.
(7g^3+4g-1)+(2g^2-6g+2)
7g^3+4g-1+2g^2-6g+2
7g^3-2g-1+2g^2+2
7g^3-2g+1+2g^2
7g^3+2g^2-2g+1
Hope this helps!
Answer:
40,320
Step-by-step explanation:
The first object in the arrangement can be chosen 8 ways. The second, 7 ways (after the first one is chosen). And so on down to the last object, which will be the only remaining one. Altogether, the number of ways you can arrange the objects is ...
8·7·6·5·4·3·2·1 = 8! = 40,320
The answer is E
step by step explanation:
Answer:
Step-by-step explanation:
What give me the question
Answer: it's A
Step-by-step explanation: Its A I bet nonono C
