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2 years ago

3^-2 expanded form

Mathematics

1 answer:

Zanzabum2 years ago

5 0

3^(-2) = 1/(3^2) = 1/(3*3) = 1/9

The rule used here is x^(-y) = 1/(x^y) to make the exponent positive.

3^2 turns into 3*3 because the exponent 2 tells us how many copies of the base '3' to multiply out.

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Somebody please help me with my homework it do tomorrow!!!

xxTIMURxx [149]

The solution to given system of equations is (x, y) = (2, -1)

Solution:

Given system of equations are:

-1x + 2y = -4 -------- eqn 1

4x + 3y = 5 ------- eqn 2

We can solve the above system of equations by elimination method

Multiply eqn 1 by 4

4(-1x + 2y = -4)

-4x + 8y = -16 ------ eqn 3

Add eqn 2 and eqn 3

4x + 3y = 5

-4x + 8y = -16

( + ) --------------------

0x + 11y = -16 + 5

11y = -11

y = -1

Substitute y = -1 in eqn 1

-1x + 2(-1) = -4

-x -2 = -4

-x = -4 + 2

-x = -2

x = 2

Check the answer:

Substitute x = 2 and y = -1 in eqn 2

4x + 3y = 5

4(2) + 3(-1) = 5

8 - 3 = 5

5 = 5

Thus the obtained answer is correct

Thus the solution to given system of equations is (x, y) = (2, -1)

8 0

2 years ago

15 + brainliest help me please

Fiesta28 [93]

2f +4f +2 -3
combine the like terms to get 6f-1

so yes they are equivalent

2f+4f+2-3 at f=3 would also be 17

8 0

2 years ago

Read 2 more answers

I really need help with this math problem.

Art [367]

Answer D.

$(36\dfrac{3}{4} +36\dfrac{3}{8} +37\dfrac{1}{2} +z):4=36\dfrac{5}{8}\\\\\\36\dfrac{6}{8} +36\dfrac{3}{8} +37\dfrac{4}{8} +z=4\cdot36\dfrac{5}{8}\\\\\\36\dfrac{6}{8} +36\dfrac{3}{8} +37\dfrac{4}{8} +z=4\cdot36\dfrac{5}{8}\\\\\\109\dfrac{13}{8}+z=4\cdot36+4\cdot\dfrac{5}{8}\\\\\\110\dfrac{5}{8}+z=144+\dfrac{20}{8} \\\\\\z=144+\dfrac{20}{8} -110-\dfrac{5}{8}\\\\\\z=34+\dfrac{15}{8}\\\\\\z=34+1\dfrac{7}{8}\\\\\\z=35\dfrac{7}{8}$

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3 years ago

12 out of 15 students play in the school band. In a class of 45 students, how many do NOT play in the band? HELP!

Elza [17]

Answer:

9 students

Step-by-step explanation:

because 15x 3 = 45 so 12x3= 36 so 45-36= 9 Can i be branliest

5 0

3 years ago

A car's velocity is modeled by

Igoryamba

In accordance with the function velocity, the car will have a complete stop after 6 seconds.

Herein we have a function of the velocity of a car (v), in feet per second, in terms of time (t), in seconds. The car stops for t > 0 and v = 0, then we have the following expression:

0.5 · t² - 10.5 · t + 45 = 0

t² - 21 · t + 90 = 0

By the quadratic formula we get the following two roots: t₁ = 15, t₂ = 6. The stopping time is the least root of the quadratic equation, that is, the car will have a complete stop after 6 seconds.

To learn more on quadratic equations: brainly.com/question/2263981

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1 year ago