Answer:
D. two real solutions
Step-by-step explanation:
p²+5 = 6p
p² - 6p +5 =0
D = b² - 4ac = (-6)² - 4*(1)*5 = 36 - 20 = 16
D > 0, so this equation has 2 real solutions
Answer:
A really out of focus picture, but I think this might be what you want.
Step-by-step explanation:
Answer:
5.38
Step-by-step explanation:
- 145.4 - 140.02 = 5.38
Replace x with π/2 - x to get the equivalent integral

but the integrand is even, so this is really just

Substitute x = 1/2 arccot(u/2), which transforms the integral to

There are lots of ways to compute this. What I did was to consider the complex contour integral

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

and it follows that

9514 1404 393
Answer:
- 0 < x < 4
- (- ∞ < x < 0) ∪ (4 < x < ∞)
- x ∈ {0, 4}
Step-by-step explanation:
1. The solution is the set of x-values for which the graph is above the x-axis, where y = 0. Those x-values are in the interval (0, 4).
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2. The solution is the set of x-values for which the graph is below the x-axis. Those x-values are in either of the two intervals (-∞, 0) or (4, ∞).
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3. The x-intercepts of the graph are x=0 or x=4.